Answer:
0.71 kg
Explanation:
L = length of the steel wire = 3.0 m
d = diameter of steel wire = 0.32 mm = 0.32 x 10⁻³ m
Area of cross-section of the steel wire is given as
A = (0.25) πd²
A = (0.25) (3.14) (0.32 x 10⁻³)²
A = 8.04 x 10⁻⁸ m²
ΔL = change in length of the wire = 1.3 mm = 1.3 x 10⁻³ m
Y = Young's modulus of steel = 20 x 10¹⁰ Nm⁻²
m = mass hanging
F = weight of the mass hanging
Young's modulus of steel is given as
F = 6.968 N
Weight of the hanging mass is given as
F = mg
6.968 = m (9.8)
m = 0.71 kg
Answer:
Check the explanation
Explanation:
To solve the problem, we need to analyze all forces acting on a bicycle individually. In question, student bikes on flat terrain so gravity force doesn't affect the road load. This is the case of uniform acceleration and deceleration so need to calculate average velocity to find Air resistance.
Kindly check the attached images below to see the step by step explanation to the question above.
Answer:
a) The exit temperature is 430 K
b) The inlet and exit areas are 0.0096 m² and 0.051 m²
Explanation:
a) Given:
T₁ = 127°C = 400 K
At 400 K, h₁ = 400.98 kJ/kg (ideal gas properties table)
The energy equation is:
For a diffuser, w = Δp = 0
The diffuser is adiabatic, q = 0
Replacing:
Where
V₁ = 250 m/s
V₂ = 40 m/s
Replacing:
Using tables, at 431.43 kJ/kg the temperature is 430 K
b) The inlet area is:
The exit area is:
Answer:
200 K
Explanation:
0 °C = 273 K
-73°C = 273 K - 73 K = 200 K
