Answer:
Distance in pc= 20parsecs
Distance in zLY= 65.2LY
Distance in AU= 4.1×10^6AU
Explanation:
Using the formular:
d = 1/p
Where d = distance
P= parallax angle in arc of second
d= 1/0.050
d= 20 parsed
Converting to Lighy years,LY :
1 PC = 3.26LY
d= 20pc × (3.26Ly/1pc)
d= 65.2Ly
To convert to AU, 206,265 AU = 1pc
d= 20pc × (2.06×10^5AU/1pc)
d= 4.1×10^6AU
For this problem, we use the equations derived for rectilinear motion at constant acceleration. The equations are:
a = (v - v₀)/t
x = v₀t + 0.5at²
where
a is acceleration
v and v₀ are the final and initial velocities, respectively
x is the distance
t is the time
First, let's determine the a to be used in the second equation:
a = (7.5 m/s - 0 m/s)/1.7 s = 4.411 m/s²
x = (0)(1.7s) + 0.5(4.411 m/s²)(1.7 s)²
x = 6.375 m
“Wave-B is every bit as invisible as Wave-A is.”
Answer:
A =150
I think it will help you bro
