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Nadusha1986 [10]
3 years ago
15

Starting from rest, a runner at a track meet reaches a speed of 7.5 m/s in 1.7 s. How far does she run during this time, assumin

g her acceleration is uniform?
Physics
1 answer:
Alex17521 [72]3 years ago
7 0
For this problem, we use the equations derived for rectilinear motion at constant acceleration. The equations are:

a = (v - v₀)/t
x = v₀t + 0.5at²
where
a is acceleration
v and v₀ are the final and initial velocities, respectively
x is the distance
t is the time

First, let's determine the a to be used in the second equation:

a = (7.5 m/s - 0 m/s)/1.7 s = 4.411 m/s²
x = (0)(1.7s) + 0.5(4.411 m/s²)(1.7 s)²
x = 6.375 m
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5 0
3 years ago
A crate with a mass of 175.5 kg is suspended from the end of a uniform boom with a mass of 94.7 kg. The upper end of the boom is
kotykmax [81]

323.5 N is the tension in the cable.

Given

Mass of crate(M) = 175.5 kg

Mass of boom(m) = 94.7 kg

The tension, T in the cable can be calculated by taking moments of force about the central point of marked X.

The Angle of the boom with the horizontal can be calculated by

tanθ = 5/10

θ = tan⁻¹(5/10) = 26.56°

Angle of the boom with horizontal is 26.56°

The angle of cable with horizontal can be calculated by

tan B = 4/10

B = tan⁻¹(4/10) = 21.80°

Angle of cable with horizontal is 21.80°

Taking moments of force about the point X

(Mcosθ + mcosθ) 0.5 = T(sin(θ +B)1

(175.5 × cos 26.56 + 94.7 × cos 26.56 )× 0.5 = T (sin(26.56 + 21.80) X 1

By calculating, we get

Tension(T) = 241.68/0.747

Tension(T) = 323.5 N

Hence, 323.5 N is the tension in the cable.

Learn more about Tension here brainly.com/question/24994188

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8 0
2 years ago
Your mother asks you to carry a load of wood to the fireplace and lower it to the hearth. In doing this you have used your arms
Evgesh-ka [11]

Answer: The correct answer is the weight of the wood.

Explanation:

Hope this helps

8 0
3 years ago
Read 2 more answers
You are fixing a transformer for a toy truck that uses an 8.0-V emf to run it. The primary coil of the transformer is broken; th
Art [367]

Answer:

a. The primary turns is 60 turns

b. The secondary voltage will be 360 volts.

Explanation:

Given data

secondary turns N2= 40 turns

primary turns N1= ?

primary voltage V1= 120 volts

secondary voltage V2= 8 volts

Applying the transformer formula which is

\frac{N1}{N2} =\frac{V1}{V2}

we can solve for N1 by substituting into the equation above

\frac{N1}{40} =\frac{120}{8} \\\ N1= \frac{40*120}{8} \\\ N1= \frac{4800}{8} \\\ N1= 60

the primary turns is 60 turns

If the primary voltage is V1 240 volts hence the secondary voltage V2 will be (to get the voltage of the secondary coil using emf substitute the values of the previously gotten N1 and N2 using V1 as 240 volts)

\frac{40}{60} =\frac{240}{V2}\\\\V2= \frac{60*240}{40} \\\\V2=\frac{ 14400}{40} \\\\V2= 360

the secondary voltage will be 360 volts.

6 0
3 years ago
A certain piece of metal (density 9.45 grams per cubic centimeter) has the shape of a hockey puck with a diameter of 13 cm and a
atroni [7]

Answer:

0.0195 m

Explanation:

\rho _{p} = density of hockey puck = 9.45 gcm⁻³ = 9450 kgm³

d_{p} = diameter of hockey puck = 13 cm = 0.13 m

h_{p} = height of hockey puck = 2.8 cm = 0.028 m

\rho _{m} = density of mercury = 13.6 gcm⁻³ = 13600 kgm³

d = depth of puck below surface of mercury

According to Archimedes principle, the weight of puck is balanced by the weight of mercury displaced by puck

Weight of mercury displaced = Weight of puck

\rho _{m} (0.25)(\pi d_{p}^{2} d ) g = \rho _{p} (0.25)(\pi d_{p}^{2} h_{p} ) g\\\rho _{m} ( d ) = \rho _{p} ( h_{p} )\\(13600) d = (9450) (0.028)\\d = 0.0195 m

7 0
3 years ago
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