What does a fire burn a hole right in the middle of the chair???

A car is parked on a cliff overlooking the ocean on an incline that makes an angle of 24.0° below the horizontal. The negligent

anzhelika [568]

Answer:

The position is $P = 47.4 \ m$ relative to the base of the ocean

Explanation:

From the question we are told that

The angle made by the incline with the horizontal is $\theta = 24.0 ^o$

The constant acceleration is $a = 3.82 \ m/s^2$

The distance covered is $d = 60.0 \ m$

The height of the cliff is $h = 50 .0 \ m$

The velocity of the car is mathematically represented as

$v^2 = u^2 + 2ad$

The initial velocity of the car is u= 0

So

$v^2 = 2ad$

substituting values

$v^2 = 2 * 3.82 * 60$

$v = 21.4 \ m/s$

The vertical component of this velocity is

$v_v = -v * sin(\theta )$

substituting values

$v_v = -21.4 * sin(24.0)$

$v_v = -8.7 \ m/s$

The negative sign is because is moving in the negative direction of the y-axis

The horizontal component of this velocity is

$v_h = v * cos (\theta)$

$v_h = 21.4 * cos (24.0)$

$v_h = 19.5 \ m/s$

Now according to equation of motion we have

$h = v_v*t - \frac{1}{2} * g t^2$

substituting values

$50 = -8.7 t - \frac{1}{2} * 9.8 t^2$

$4.9t^2 +8.7t -50 = 0$

using quadratic equation we have that

$t_1 = 2.42\ s \ and\ t_2 = -4.20\ s$

given that time cannot be negative

$t = 2.42 \ s$

The car’s position relative to the base of the cliff when the car lands in the ocean is mathematically evaluate as

$P = v_h * t$

substituting values

$P = 19.5 * 2.43$

$P = 47.4 \ m$

5 0

3 years ago

Would you be doing more work going up the stairs twice as fast?

SSSSS [86.1K]

If you use the stairs at normal speed, you will survive longer, and go up higher.
When going up the stairs twice as fast, you lose energy more quickly, but height would remain the same.

7 0

3 years ago

Read 2 more answers

A student writes the following script for a scene in a futuristic movie: A rocket ship is landing on the Moon where many astrona

Sav [38]

Answer: No crash landing on the surface of the moon and there is no vibration due to low acceleration due to gravity.

Explanation:

The rocket ship can't land on the surface of the moon because it depends on winged flight for its controlled descent to the surface of the Earth. Since the moon has no real atmosphere, the wings would not be able to glide the craft smoothly to the moon's surface.

The acceleration due to gravity in the moon is very low compared to the earth. The astronauts cannot experience vibration ripple through the Moon’s surface beneath their feet because the low level acceleration due to gravity will drastically affect the weight of the ship.

6 0

3 years ago

The current theory of the structure of the

IRISSAK [1]

1) The mass of the continent is $3.3\cdot 10^{21} kg$

2) The kinetic energy of the continent is 624 J

3) The speed of the jogger must be 4 m/s

Explanation:

1)

We start by finding the volume of the continent. We have:

$L = 5850 km = 5.85\cdot 10^6 m$ is the side

$t = 35 km = 3.5\cdot 10^4 m$ is the depth

So the volume is

$V=L^2 t = (5.85\cdot 10^6)^2 (3.5\cdot 10^4)=1.20\cdot 10^{18} m^3$

We also know that its density is

$d=2750 kg/m^3$

Therefore, we can find the mass by multiplying volume by density:

$m=dV=(2750)(1.20\cdot 10^{18})=3.3\cdot 10^{21} kg$

2)

The kinetic energy of the continent is given by:

$K=\frac{1}{2}mv^2$

where

$m=3.3\cdot 10^{21} kg$ is its mass

v = 3.2 cm/year is the speed

We have to convert the speed into m/s. We have:

3.2 cm = 0.032 m

$1 year = 1(365)(24)(60)(60)=3.15\cdot 10^7 s$

So, the speed is:

$v=\frac{0.032 m}{3.15 \cdot 10^7 s}=1.02\cdot 10^{-9} m/s$

So, we can now find the kinetic energy:

$K=\frac{1}{2}(1.20\cdot 10^{21})(1.02\cdot 10^{-9})^2=624 J$

3)

Here we have a jogger of mass

m = 78 kg

And the jogger has the same kinetic energy of the continent, so

K = 624 J

The kinetic energy of the jogger is given by

$K=\frac{1}{2}mv^2$

where v is the speed of the jogger.

Solving for v, we find the speed that the jogger must have:

$v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(624)}{78}}=4 m/s$

Learn more about kinetic energy:

brainly.com/question/6536722

#LearnwithBrainly

3 0

3 years ago

Is there any change in the pressure of container filled with water when the volumed is increased

marshall27 [118]

Not really the volume of a container is simply length X width X depth so just how big the container unless the water is pressurized by some sort of weight or if the containers air pressure is lowered

7 0

3 years ago