Answer: <em>The number placed in front of a compound to balance a chemical reaction is called </em><em><u>coefficient</u></em>.
Explanation:
Assume this general form for a <em>chemical equation</em>:
- <em>a</em>A + <em>b</em>B → <em>c</em>C + <em>d</em>D
The letters <em>a, b, c, </em>and <em>d,</em> in front of each compound A, B, C, and D, are called coefficients and indicate the number of formula units (molecules or ions) that take part in the equation.
Those coefficients are needed to <em>balance the equation</em> and ensure compliance with the law of mass conservation.
This example shows it:
- Word equation: hydrogen + oxygen yields water
- Chemical equation: H₂ (g) + O₂(g) → H₂O(g)
- Balance, adding the coefficients so that the number of each kind of atoms is the same on the left and the right of the chemical equation:
H₂ (g) + 2O₂(g) → 2H₂O(g)
In that equation:
- The coefficient of H₂ (g) on the left is 1 (it is not written)
- The coefficient of O₂(g) on the left is 2
- The coefficient of H₂O(g) on the right is 2
You read it as: 1 mole of gaseous hydrogen and 2 moles of gaseous oxygen yield 2 moles of water vapor.
P₁ = 0.90 atm
V₁ = 50.0 mL
T₁ = 298 K
P₂ = 1 atm
T₂ = 273 K
V₂ = P₁ x V₁ x T₂ / T₁ x P₂
V₂ = 0.90 x 50.0 x 273 / 298 x 1
V₂ = 12285 / 298
V₂ = 41 mL
Answer (1)
hope this helps!
Answer:
19.29 g.cm⁻³
Solution:
Data Given:
Mass = 301 g
Volume = 15.6 cm³
Formula Used:
Density = Mass ÷ Volume
Putting values,
Density = 301 g ÷ 15.6 cm³
Density = 19.29 g.cm⁻³
1AlBr3+ 3K ---> 3KBr + 1Al
Answer:
In the 5th cycle rinse, the residual concentration of the solution is < 0.00001M
Explanation:
In each rinse cycle, the dilution that you are doing of the solution is from 1.00mL to 10.00mL, that is a dilution of 10
In the first rinse the concentration must be of 0.9M 10 = 0.09M
2nd = 0.009M
3rd = 0.0009M
4th = 0.00009M
5th = 0.000009M →
<h3>In the 5th cycle rinse, the residual concentration of the solution is < 0.00001M</h3>
