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m_a_m_a [10]
3 years ago
8

Which one will fill up first?? and explain how?,​

Chemistry
2 answers:
Svetlanka [38]3 years ago
7 0

Answer:

5th fill first....

hope it's help you

soldi70 [24.7K]3 years ago
3 0

Answer:

5

Explanation:

because 2 box is close mark brainlist plss

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What happens when chocolate get heated?
Leokris [45]

Answer:

Chocolate melts and becomes really sticky once heated.

Add-on:

hope that helped at all.

8 0
3 years ago
Read 2 more answers
the buret is dirty and drops of NaOH cling to the side walls of the buret as it drained. How does this affect the result for NaO
kykrilka [37]
Since this has to do with titration, the measured volume of NaOH used would be less than the actual volume used because some of the unused NaOH would cling to the sides of the buret and therefore wouldn't factor into the measurement

Hope this helps
6 0
4 years ago
Most substances become less dense as the temperature increases. Which substance is an exception to this rule
stealth61 [152]
The substance is water
6 0
4 years ago
Read 2 more answers
Calculate the value of ΔG∘rxnΔGrxn∘ for the following reaction at 296 K. Ka = 2.9 × 10–8 and assume Ka does not change significa
oee [108]

Answer:

\Delta G_{rxn}=42.7\frac{kJ}{mol}

Explanation:

In this case, for the dissociation of hypochlorous acid, we know that the acid dissociation constant (Ka) is 2.9x10⁻⁸, which is related with the Gibbs free energy as shown below:

\Delta G_{rxn}=-RTln(K)

But in this case K is just Ka, therefore, at 296 K, it turns out:

\Delta G_{rxn}=-8.314\frac{J}{mol*K}*296K*ln(2.9x10^{-8})\\\\\Delta G_{rxn}=42.7\frac{kJ}{mol}

Such result, means that the reaction is nonspontaneous at the given temperature, it means it is not favorable (not easily occurring).

Best regards.

7 0
3 years ago
Determine the empirical formula for a compound that is 70.79% carbon, 8.91% hydrogen, 4.59% nitrogen, and 15.72% oxygen.
Debora [2.8K]

Answer:

The answer to your question is:       C₁₈ H₂₇ N O₃

Explanation:

Data

Carbon = 70.79 g

Hydrogen = 8.91 g

Nitrogen = 4.58 g

Oxygen = 15.72 g

Process

AT C = 12 g

AT H = 1 g

AT N = 14 g

AT O = 16 g

                   Carbon

                                  12 g ------------------------  1 mol

                           70.79  g -------------------------   x

                                 x = (70.79 x 1) / 12

                                 x = 5.9 mol of C

                  Hydrogen

                                   1 g -----------------------  1 mol

                                8.91 g ---------------------   x

                                  x = (8.91 x 1) / 1

                                  x = 8.91 mol of H

                  Nitrogen

                                 14 g ---------------------- 1 mol

                                4.58 g -------------------   x

                                   x = (4.58 x 1) / 14

                                   x = 0.33 mol

                  Oxygen

                               16 g ------------------------  1 mol

                               15.72 g --------------------   x

                                  x = (15.72 x 1)/16

                                 x = 0.98

Divide by the lowest number of moles

Carbon               5.9 / 0.33     =  17.9   ≈ 18

Hydrogen           8.91 /  0.33  =   27

Nitrogen             0.33 / 0.33  =    1

Oxygen               0.98 / 0.33 =    2.9  ≈ 3

                             C₁₈ H₂₇ N O₃

4 0
4 years ago
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