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pentagon [3]
3 years ago
15

1. Justin jogs 3 miles every morning. He

Mathematics
1 answer:
hammer [34]3 years ago
8 0

Answer:

7

Step-by-step explanation:

He jobs 7 miles every morning:

3 miles in the morning, and 4 miles in the evening.

Which equals 7.

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A doctor wants her patient to take 60 milligrams of vitamin C and 20 centigrams of vitamin B6 daily. How many total milligrams o
irakobra [83]
Just as the conversion for millimeters to centimeters is, the conversion used here will be:
10 milligram = 1 centigram
Milligrams of vitamin B6 = 20 x 10
Milligrams of vitamin B6 = 200 mg

Total milligrams = 200 + 60
Total milligrams = 260
8 0
3 years ago
To begin solving this system of linear equations by elimination you can add the equations. 3x + 2y = 38 5x – 2y = -30 8x = 8 Thi
WITCHER [35]

Answer:

D

Step-by-step explanation:

Addition property of equality

3 0
3 years ago
During the first hour of operation the farm stand owner sold 15% of the apples he had. On the second hour he sold 20% of the rem
zzz [600]

Answer:

38.25 kg

Step-by-step explanation:

Let the number of apples sold = x

Now, on the first hour he sold 15% of the apples i.e. he sold 0.15x kg of apples.

So, the remaining apples = x - 0.15x = 0.85x

Further, on the second hour he sold 20% of the remaining apples i.e. he sold 0.20 × 0.85x = 0.17x kg of apples.

Thus, the remaining apples = 0.85x - 0.17x = 0.68x

Then, on the third hour he sold 25% of the remaining apples i.e. he sold 0.25 × 0.68x = 0.17x kg of apples.

So, the remaining apples = 0.68x - 0.17x = 0.51x

Moreover, on the fourth hour he will sell 30% ( i.e. 5% more of 25% ) of the remaining apples i.e. he sold 0.30 × 0.51x = 0.153x kg of apples.

As, during the second hour, he sold 25.5 kg of apples.

Then, 0.17x = 25.5 i.e. x=\frac{25.5}{0.17} i.e. x = 250

Hence, during the fourth hour, he will sell 0.153x = 0.153 × 250 = 38.25 kg of apples.

7 0
3 years ago
Can u tell me the answer
slamgirl [31]

Answer:

1

Step-by-step explanation:

just substitute q for 1 and then square 1

5 0
4 years ago
Ten runners join a race. In how many possible ways can they be arranged as first, second, and third placer? Pls answer
Daniel [21]
Ans: 720

<span>This is equal to the number of different arrangements of three persons from a group of 10 persons </span>

Required number of ways = 10P3 = 720

OR can be solved in this way
select 3 runners (10C3 ways)
These 3 runners can be arranged in 3! ways
<span>Total = 10C3×3! = 720

</span>
5 0
3 years ago
Read 2 more answers
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