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snow_tiger [21]
2 years ago
15

Mabel had a skating rink party for her birthday the cost to rent the party room was $75 the cost of the ticket for each of the 6

people who came to the party was $8
Mathematics
2 answers:
nikitadnepr [17]2 years ago
7 0

Answer:

Mabel has a skating rink party for her birthday. The cost to rent the party room was $75. The cost of the ticket for each of the 6 people who came to the party was $8. What was the total cost of the party?

the party cost a total of $123

Step-by-step explanation:

we are asked to calculate the cost spent on a party

the room in which the part was hosted cost  $75 and the 6 people invited paid a $8  ticket fee.

To calculate this, we simply add the amount of the ticket plus the amount for the room.

The total amount paid for the ticket would be 6 * 8 = $48

Adding this to the room cost will yield ;

the room in which the part was hosted +  6 people invited

$48 + $75 = $123

its 123 because they rented the party room and its $75 and 6 people came the entrance is $8........ so 8 x 6 = 48 then add that to 75 which is $123

Hence, the party cost a total of $123

Aleksandr [31]2 years ago
4 0

Answer:

$123

Step-by-step explanation:

The question isn’t complete, it is however completed below;

Mabel has a skating rink party for her birthday. The cost to rent the party room was $75. The cost of the ticket for each of the 6 people who came to the party was $8. What was the total cost of the party?

Let’s solve now!

In this question, we are asked to calculate the cost spent on a party if the room in which the part was hosted cost a certain amount and the 6 people invited paid a certain ticket fee.

To calculate this, we simply add the amount of the ticket plus the amount for the room.

The total amount paid for the ticket would be 6 * 8 = $48

Adding this to the room cost will yield ;

$48 + $75 = $123

Hence the party cost a total of $123

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Answer:

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Step-by-step explanation:

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First, convert 4^{x-3} to base 2:

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\frac{1}{2} ^{x-4} - 3 = (2^{2})^{x-3} - 2

Next, convert \frac{1}{2} ^{x-4} to base 2:

\frac{1}{2} ^{x-4} = (2^{-1})^{x-4}

(2^{-1})^{x-4} - 3 =  (2^{2})^{x-3} - 2

Apply exponent rule: (a^{b})^{c} = a^{bc}:

(2^{-1})^{x-4} = 2^{-1*(x-4)}

2^{-1*(x-4)} - 3 = (2^{2})^{x-3} - 2

Apply exponent rule: (a^{b})^{c} = a^{bc}:

(2^{2})^{x-3} = 2^{2(x-3)}

2^{-1*(x-4)} - 3 = 2^{2(x-3)} - 2

Apply exponent rule: a^{b+c} = a^{b}a^{c}:

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Apply exponent rule: (a^{b})^{c} = a^{bc}:

2^{-1x} = (2^{x})^{-1}, 2^{2x} = (2^{x})^{2}

(2^{x})^{-1} * 2^{4} - 3 = (2^{x})^{2} * 2^{-6} - 2

Rewrite the equation with 2^{x} = u:

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Solve u^{-1} * 2^{4} - 3 = u^{2} * 2^{-6} - 2:

u^{-1} * 2^{4} - 3 = u^{2} * 2^{-6} - 2

Refine:

\frac{16}{u} - 3 = \frac{1}{64}u^{2} - 2

Add 3 to both sides:

\frac{16}{u} - 3 + 3 = \frac{1}{64}u^{2} - 2 + 3

Simplify:

\frac{16}{u} = \frac{1}{64}u^{2} + 1

Multiply by the Least Common Multiplier (64u):

\frac{16}{u} * 64u = \frac{1}{64}u^{2} + 1 * 64u

Simplify:

\frac{16}{u} * 64u = \frac{1}{64}u^{2} + 1 * 64u

Simplify \frac{16}{u} * 64u:

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1024 = u^{3} + 64u

Solve for u:

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Answer:

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