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Artemon [7]
3 years ago
11

Which sign will you put in between [ 120 ……… (3 / 11) ], so that the answer is the highest number

Mathematics
1 answer:
Natasha2012 [34]3 years ago
6 0

Answer:

d) ÷

Step-by-step explanation:

120 ÷ 3/11 = 440

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To find g(x + 7), what do you substitute for x in the function g(x) = 4x - 2?
AlexFokin [52]

Answer: x+7

Step-by-step explanation:

g(x) = 4x - 2

g(x+7)=4(x+7)-2

Substitute (x+7)

8 0
2 years ago
J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.
melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

                      P.Q.  =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }  ~ t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean for mail-order sales = $74.50

\bar X_2 = sample mean for internet sales = $84.40

s_1 = sample standard deviation for mail-order purchases = $17.25

s_2 = sample standard deviation for internet purchases = $21.25

n_1 = sample of sales receipts for mail-order purchases = 16

n_2 = sample of sales receipts for internet purchases = 9

Also,  s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }  =  \sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} } = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by (\mu_1-\mu_2).

Now, 99% confidence interval for (\mu_1-\mu_2) is given by;

             = (\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_)  \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

          = (74.50-84.40) \pm (2.807  \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})

          = [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

5 0
3 years ago
What <br> is (81m^6)^1/2 simplified
ANEK [815]
(81m^6)^1/2 = (3^4*1/2) (m^6*1/2) = 3²m³
7 0
3 years ago
The growth rate of a vine is proportional to the square root of its current length. If the length of the vine is 16 feet initial
kkurt [141]
C 938 ft , I just took the test
4 0
3 years ago
Ines has 3/5 quart of orange juice she drinks 1/3 quart how much orange juice does she now have
RoseWind [281]

Answer: 4/15

Step-by-step explanation:

3/5 -1/3 = 4/15

3 0
4 years ago
Read 2 more answers
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