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Artemon [7]
3 years ago
11

Which sign will you put in between [ 120 ……… (3 / 11) ], so that the answer is the highest number

Mathematics
1 answer:
Natasha2012 [34]3 years ago
6 0

Answer:

d) ÷

Step-by-step explanation:

120 ÷ 3/11 = 440

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Financial maths-- multiple choice!!!
Zinaida [17]

Answer:

liquidity

Step-by-step explanation:

when the bank gets only electronic money transfers, they don't get actual money. so, they can use that only for other electronic transfers, but if there is the need for actual money (e.g. a lot of people need a cash payout), the bank is then not able to do that. they don't have enough cash = they are not liquid.

which can actually lead to insolvency.

4 0
3 years ago
PLZ HELP ASAP RIGHT TRIANGLES
borishaifa [10]
The correct answer is: AB = 3.11

Explanation:
Since

cos(\theta) =  \frac{base}{hypotenuse} --- (1)
\theta = 50°
base = 2

And hypotenuse = AB

Plug in the values in (1):
(1) => cos(50°) = 2/AB

=> AB = 2/0.643
=> AB = 3.11
6 0
3 years ago
I need help solving this w/ steps please
Leya [2.2K]
The answer to this question is 0.527
3 0
3 years ago
Read 2 more answers
Sin theta+costheta/sintheta -costheta+sintheta-costheta/sintheta+costheta=2sec2/tan2 theta -1
sleet_krkn [62]

\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}=\dfrac{2sec^2\theta}{tan^2\theta-1}

From Left side:

\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}\bigg(\dfrac{sin\theta+cos\theta}{sin\theta+cos\theta}\bigg)+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}\bigg(\dfrac{sin\theta-cos\theta}{sin\theta-cos\theta}\bigg)

\dfrac{sin^2\theta+2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}+\dfrac{sin^2\theta-2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}

NOTE: sin²θ + cos²θ = 1

\dfrac{1 + 2cos\theta sin\theta}{sin^2\theta-cos^2\theta}+\dfrac{1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}

\dfrac{1 + 2cos\theta sin\theta+1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}

\dfrac{2}{sin^2\theta-cos^2\theta}

\dfrac{2}{\bigg(sin^2\theta-cos^2\theta\bigg)\bigg(\dfrac{cos^2\theta}{cos^2\theta}\bigg)}

\dfrac{2sec^2\theta}{\dfrac{sin^2\theta}{cos^2\theta}-\dfrac{cos^2\theta}{cos^2\theta}}

\dfrac{2sec^2\theta}{tan^2\theta-1}

Left side = Right side <em>so proof is complete</em>

8 0
3 years ago
Read 2 more answers
Graph for 4x + 3y = -3
Serga [27]

Answer:

Your answer is: Slope = -\frac{4}{3} Y-intercept = (0,-1)

Graph the line using the slope and y-intercept, or two points.

Step-by-step explanation:

Graph Below : ↓

Hope this helped : )

6 0
2 years ago
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