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3 years ago

When particles get close to the surface, they interact with atoms in

Physics

1 answer:

alex41 [277]3 years ago

4 0

Is there anything else in the page I think it’s missing a part

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Hugs 5 things your dog might do when hugged

Nezavi [6.7K]

1. growl: most certainly the dog is going to start growling, but not in a negative, aggressive way, but rather in a surprised, amused way
2. li.ck: the dog will definitely li.ck you, as this is what dogs do when approached
3. pant: dogs pant all the time, especially if it's hot outside, so hugging them makes no difference
4. play: they will want to play with you once they see you love them and want to be around them
5. try to run: some dogs aren't really into hugging, which is why they will try to run away from you because they are confused

4 0

3 years ago

Calculate the acceleration due to gravity at a point 1000km above the surface of the earth?

klio [65]

Answer:

g' = 6.74 m/s²

Explanation:

R = 6400km

h = 1000km

g = 9.81m/s

g' = g(1 - 2h/R)

Goodluck

3 0

4 years ago

Formula for acceleration?

adell [148]

Answer:

Force = mass * acceleration

F = m*a

Hope this helps

3 0

3 years ago

When an object accelerates, what about its motion changes? Question 1 options: Speed must change, but not velocity. Both speed a

QveST [7]

Answer:

The velocity must change but not speed.

Explanation:

Velocity is defined as the displacement by time. Whereas speed is expressed as the distance between two successive positions of the body to the time interval it took to travel.

Velocity, V = D / t m/s

Speed, s = d /t m/s

Velocity is a vector quantity that has a magnitude and direction.
The speed is a scalar quantity having only the magnitude.
At any instant of time, the magnitude of the velocity is always equal to the magnitude of the speed. The magnitude of velocity, |v | = magnitude of speed, |v |. The magnitude is always positive
The acceleration of a body is defined as the rate of change of velocity to time.

a = (v - u) / t m/s²

If a body is accelerating, It varies its velocity with respect to time.
In case of uniform circular motion, the speed remains constant, but the velocity changes continuously.

So, in the case of circular motion if an object accelerates, velocity must change but speed remains constant.

5 0

4 years ago

In measuring the width of a hair sample, a light of wavelength 500 nm is used. The hair sample is 40 um in radius. With the scre

sergejj [24]

Answer:

The distance of the second dark band away from the central bright spot be located is $5.625\times10^{-2}\ m$

Explanation:

Given that,

Wave length = 500 nm

Radius $d= 40\ \mu m$

Distance from the hair sample D= 6 m

We need to calculate the distance of the second dark band away from the central bright spot be located

$\sin\theta=\dfrac{y}{D}$

$\sin\theta=\dfrac{y}{6}$

Using formula for dark fringe

$(n-\dfrac{1}{2})\lambda=2d\sin\theta$

Put the value into the formula

$(2-\dfrac{1}{2})\times500\times10^{-9}=2\times40\times10^{-6}\times\dfrac{y}{6}$

$y=\dfrac{(2-\dfrac{1}{2})\times500\times10^{-9}\times6}{2\times40\times10^{-6}}$

$y=0.05625\ m$

$y=5.625\times10^{-2}\ m$

Hence, The distance of the second dark band away from the central bright spot be located is $5.625\times10^{-2}\ m$

6 0

3 years ago