Answer:
Explanation:
The volume of the tank = 50 kton
50 kton = 5 × 10⁷ kg
Since 18 grams of water will contain: 10 electrons × 6.023 × 10²³
Then;
5× 10⁷ kg will contain
= 1.67 × 10³⁴ electrons
(b)
Suppose:
Then;
10⁻⁶ of
Thus, the number of high energy neutrinos which will interact with water is:
=
=
=
For 1.67 × 10³⁴ electrons, the detection rate is:
= 9.668 per day