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Evgen [1.6K]
3 years ago
5

NEEED HELPPPP ASAP PLEASEEE!!!! ONLY THE LAST ONE TO COMPLETE IM HAVING TROUBLE PLEASE

Mathematics
1 answer:
sergeinik [125]3 years ago
7 0

The answer would be 1.52727...

To solve this, subtract 283-199 is 84. Then divide 84 by 55 since 55 is mph of the car. Then you would divide the 84/55. After, the calculation should be 1.52727...

So, the answer/ how much time it takes from Tallahassee to Live Oak is 1.5 hours. (1.52727, 1.53)

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The number of eggs in the refrigerator e decreased by 9 equals 17.
alexandr402 [8]

Answer:

x-9=17

Step-by-step explanation:

x=eggs in the fridge

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3 years ago
I need help on 6 -9 use the chart please I need help on it !!!!
natita [175]

Answer:

6 is the first one on the accounting cleark and 9 is 2,500

Step-by-step explanation:

No explanation i just wanted to be nice anhd help you with out anything :)

3 0
3 years ago
Not really math 20 points for this though what are Fiona's parents names
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King Harold + Queen Lilian = Fiona
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How many times does 81,000 goes into 8,000
Effectus [21]
Zero. That number cannot go into that one
8 0
3 years ago
The average yield of the standard variety off soybeans per acre on a farm in a region is 48.8 bushels per acre, with a standard
I am Lyosha [343]

Answer:

z=\frac{53.4-48.8}{\frac{12}{\sqrt{36}}}=2.3  

p_v =P(Z>2.3)=1-P(Z  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 48.8 at 1% of signficance.  

Step-by-step explanation:

1) Data given and notation  

\bar X=53.4 represent the sample mean

\sigma=12 represent the population standard deviation assumed

n=36 sample size  

\mu_o =48.8 represent the value that we want to test  

\alpha=0.01 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

2) State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is higher than 48.8, the system of hypothesis would be:  

Null hypothesis:\mu \leq 48  

Alternative hypothesis:\mu > 48  

Since we assume that know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

3) Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{53.4-48.8}{\frac{12}{\sqrt{36}}}=2.3  

4)P-value  

Since is a right tailed test the p value would be:  

p_v =P(Z>2.3)=1-P(Z  

5) Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 48.8 at 1% of signficance.  

3 0
3 years ago
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