9a) False, The dimensions are 10 x 20
b) True, 10 x 20 = 200
c) 10-6=4 (right side minus left side)
26-20=6 (bottom line minus top line)
d) True, Area of a triangle = (base x height) / 2
The base is 6 and the height is 4, so 6 x 4= 24 / 2 =12
e) True, the total area is equal to the triangle area plus the rectangles area.
so, 200+12= 212
Answer:
2√5 - 3
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
- Terms/Coefficients
- Expand by FOIL
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
(√5 + 4)(√5 - 2)
<u>Step 2: Simplify</u>
- Expand [FOIL]: (√5)² - 2√5 + 4√5 - 8
- Combine like terms: (√5)² + 2√5 - 8
- Evaluate exponents: 5 + 2√5 - 8
- Combine like terms: 2√5 - 3
Answer:
B
Step-by-step explanation:
B has a slope of 7 while A has a slope of 6.
slope of B 14-7/2-1 = 7
A slope is y= mx+b and m is the slope. so 6.
Answer:
± 27.33 ft
Step-by-step explanation:
For the given problem, we can estimate the initial and final coordinates of the line of the ball path as (-40,-50) and (0,0). Therefore, the slope is:
(-50-0)/(-40-0) = 50/40 = 1.25
Similarly, we can estimate the slope of a perpendicular line to the line of the ball path as: -1*(1/1.25) = -0.8.
Therefore, using (0,0) and the slope -0.8, the equation of the perpendicular line is: -0.8 = (y-0)/(x-0);
-0.8 = y/x
y = -0.8x
Furthermore, we are given the circle radius as 35 ft and we can use the distance formula to find the two points 35 ft far from the origin:
35^2 = x^2 + y^2
y = -0.8x
35^2 = x^2 + (-0.8x)^2
1225 = (x^2 + 0.64x^2)
1225 = 1.64x^2
x^2 = 1225/1.64 = 746.95
x = sqrt(746.95) = ± 27.33 ft
Answer:
True.
Step-by-step explanation:
Remember that the horizontal line test checks if a function is one-to-one. If a horizontal line passes through a graph more than once, the function has more than one x-value for at least one y-value.