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2 years ago

Ali bought his mom 2 dozen (24) of roses. 1/3 of them are red and the rest are pink. How many are pink

Mathematics

1 answer:

shepuryov [24]2 years ago

7 0

Answer:

there are 16 pink roses

Step-by-step explanation:

Number of pink roses = fraction of pink roses x total number of roses bought

fraction of pink roses = 1 - fraction of red roses

1 - 1/3

= 3/3 - 1/3 = 2/3

Number of pink roses = 2/3 x 24 = 16

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In Mr. Jegou's neighborhood 35% of the houses are blue. Write the

ivann1987 [24]

Answer:

Fraction: 3/20

Decimal: 0.35

Step-by-step explanation:

a) 100% - 35% = 65

So, 65% of the houses are NOT blue.

..............................................

Fraction: 3/20

Decimal: 0.35

3 0

2 years ago

Read 2 more answers

Simplify 3x³(x+2)+2x(x²+3x)

max2010maxim [7]

Answer:

${3x}^{4} + {8x}^{3} + {6x}^{2}$

Step-by-step explanation:

${3x}^{3} (x + 2) + 2x( {x}^{2} + 3x)$

${3x}^{4} + {6x}^{3} + {2x}^{3} + {6x}^{2}$

${3x}^{4} + {8x}^{3} + {6x}^{2}$

<h3>Hope it is helpful...</h3>

8 0

3 years ago

The average income, I, in dollars, of a lawyer with an age of x years is modeled with the following function:

Alinara [238K]

The answer is 37 years old.

I = -425x² + 45500x -650000
I = 450000

-425x² + 45500x -650000 = 450000
-425x² + 45500x - 650000 - 450000 = 0
-425x² + 45500x - 1100000 = 0

Divide all factors by 25:
- 17x² + 1820x - 44000 = 0

This is quadratic equation (ax² + bx + c = 0)
$x_{1,2} = \frac{-b+/- \sqrt{ b^{2}-4ac } }{2a} = \frac{-1820+/- \sqrt{ 1820^{2}-4*(-17)*(-44000) } }{2*(-17)} = \\ \\ = \frac{-1820+/- \sqrt{3312400-2992000 } }{-34} = \frac{-1820+/- \sqrt{320400} }{-34} =\frac{-1820+/- 566}{-34} \\ \\ 
x_1= \frac{-1820+ 566}{-34}= -37 \\ \\ 
x_2 = \frac{-1820- 566}{-34}=70$

Since, the youngest age is needed, the correct answer is x = 37

3 0

3 years ago

Please someone help please pls

mario62 [17]

Answer:

h= $h= \frac{5R^{3} }{LU}$

Step-by-step explanation:

1.) You must isolate the h from the equation by dividing both sides by L (or multiply by its reciprocal, which in this case, the reciprocal on L is $\frac{1}{L}$ .....So it would look like: