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Dominik [7]
3 years ago
5

Jack walks outside in the afternoon and noticed the clouds are very dark. He states that it looks like it will rain very soon. H

is statement can be classified as A) prediction B) observation C) inference D) hypothesis
Chemistry
2 answers:
Kay [80]3 years ago
7 0

Answer:

I think it would be A but it might be B please tell if wrong

tatiyna3 years ago
7 0

Answer:

A prediction

Explanation:

A prediction, or forecast, is a statement about a future event. They are often, but not always, based upon experience or knowledge and jack is using his knowledge on clouds to predict when it is going to rain.

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A child is swinging back and forth on a swing. Changes in her kinetic and potential energy are happening each moment. At which p
dedylja [7]

Answer:

The maximum potential energy of the child will be maximum at the two end points.  

The maximum kinetic energy of the <em>child </em>occurs at the lowest point of the swing.  

The potential energy of the child depends on the displacement of the child.  

P.E = mgh  

The maximum height attained occurs at the two end points of her swing motion.  

Thus, the maximum potential energy of the child will be maximum at the two end points.

The kinetic energy of the child depends on the velocity of the child  

K.E = ¹/₂mv²  

The maximum velocity of the swing occurs at the lowest point of the swing.  

Thus, the maximum kinetic energy of the child occurs at the lowest point of the swing.

Hope this helps!

5 0
3 years ago
Read 2 more answers
How are electromagnetic waves are measured In three ways
Tatiana [17]

Ultraviolet Rays, Radio Waves, and Gamma Rays.

:)

5 0
3 years ago
Balance the chemical equation below: CO2 + H2O + 2678 kJ-&gt; C6H1206 + O2 a. How many moles of H20 are involved in this reactio
11Alexandr11 [23.1K]

Answer:

a) 6 mol H2O

b) this reaction is endothermic

c) when 1 mol of CO2 is used, in the reaction they occur 0.5025 KJ

Explanation:

balanced eq:

  • 6CO2 + 6H2O + 2678 KJ ↔ C6H12O6 + 6O2

                                         6 - C - 6

                                         18 - O - 18

                                          12 - H - 12

a) mol H2O = 6 mol.......from balanced equation.

b) ΔE = 2678 KJ....... this reaction absorbs heat ( ΔE is positive )

c)    1 gramo C6H12O6 ≅ 4 cal

  • Mw C6H12O6 = 180.156 g/mol

⇒ 1mol CO2 * ( mol C6H12O6 / 6mol CO2 ) =0.166 mol C6H12O6

⇒ 0.166mol C6H12O6 * ( 180.156 g C6H12O6 / mol ) = 30.026g C6H12O6

⇒30.026 gC6H12O6 * ( 4 cal / gC6H12O6 ) * ( Kcal / 1000 cal ) * (4184 J / Kcal ) * ( KJ / 1000 J ) = 0.5025 KJ C6H12O6.

8 0
3 years ago
Dinitrogen pentoxide decomposes in the gas phase to form nitrogen dioxide and oxygen gas. The reaction is first order in dinitro
vitfil [10]

Answer : The partial pressure of O_2 is, 222.93 torr

Explanation :  

Half-life = 2.81 hr = 168.6 min

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{168.6min}

k=4.11\times 10^{-3}min^{-1}

Now we have to calculate the partial pressure of O_2

The balanced chemical reaction is:

                           2N_2O_5(g)\rightarrow 4NO_2(g)+O_2(g)

Initial pressure   760                0             0

At eqm.             (760-2x)            4x            x

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{P_o}{P_t}

where,

k = rate constant

t = time passed by the sample  = 215 min

a = initial pressure of N_2O_5 = 760 torr

a - x = pressure of N_2O_5 at equilibrium = (760-2x) torr

Now put all the given values in above equation, we get:

215=\frac{2.303}{4.11\times 10^{-3}}\log\frac{760}{760-2x}

x=222.93torr

The partial pressure of O_2 = x = 222.93 torr

7 0
3 years ago
A geologist is studying an area where stream erosion and deposition are the dominant surface processes. He notices that all of t
mixas84 [53]

Answer: A)

Explanation:

the deposition environment has changed from wind-dominated in the past to stream-dominated today.

7 0
3 years ago
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