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joja [24]
3 years ago
12

What’s all stages of matter

Chemistry
2 answers:
AnnZ [28]3 years ago
5 0

Hello, Lithommie


Here are all three states of matter


1. Solid


2. Liquid


3. Gass



If my answer helped you please leave a thank and rate it 5 stars and the most important please mark me as brainliest thank you and have the best day ever!



djverab [1.8K]3 years ago
5 0

Hi Lithommie,

Your Question:

What's all stages of matter

Answer:

  • Solid
  • Liquid
  • Gas
  • Plasma
  • Bose-Einstein Condensates
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The goose has a mass of 19.2 lb (pounds) and is flying at 7.10 miles/h (miles per hour). What is the kinetic energy of the goose
nata0808 [166]

Answer:

43.868 J

Explanation:

Kinetic energy of a body is the amount of energy possessed by a moving body. The SI unit of kinetic energy is the joule (kg⋅m²⋅s⁻²).

According to classical mechanics, kinetic energy = 1/2 m·v²

Where, m= mass in kg and v= velocity in m/s

Given: m = 19.2 lb and v = 7.10 miles/h

Since, 1 lb= 0.453592 kg

∴ m = 19.2 lb = 19.2 × 0.453592 kg = 8.709 kg

Also, 1 mi = 1609.34 m and 1 h = 3600 sec

∴ v = 7.10 mi/h = 7.10 × 1609.34 m ÷ 3600 sec = 3.174 m/sec

Therefore, <u>kinetic energy of the goose</u> = 1/2 m·v² = 1/2 × (8.709 kg)× (3.174 m/sec)² = 43.868 J

5 0
3 years ago
Heyy pls help anyone?
madam [21]
1a. calcium chloride (CaCl2)
b. 2HCl (aq) + Ca(OH)2 (s) —> CaCl2 (aq) + 2H2O (l)

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3 years ago
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A coffee-cup calorimeter initially contains 125 g water at 24.28C. Potassium bromide (10.5 g), also at 24.28C, is added to the w
iren2701 [21]

Answer:

The solution is given below

Explanation:

Heat, q= mc∆T

q= 125g x 4.18 J/g∙°C x (21.18x- 24.28) °C

q=  -1619.75J

NEGATIVE SIGN INDICATES THAT HEAT IS ABSORBED.

Enthalpy Change, ∆H = 1619.75 7/ 10.5 g

                                     = 154.26 J/g

No. of moles of KBr = Mass of KBr/ Molecular Weight of KBr

                                =10.5g/119gmol-1

                                =0.088 mol

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6 0
3 years ago
238,2U --&gt; 234Th +<br> 90
stiv31 [10]

Answer:

\\_{2}^{4} \alpha

Explanation:

In this question, we wish to find the missing nuclei for the equation:

\\_{92}^{238} U\rightarrow _{90}^{234} Th + _{Z}^{A} X

In order to find the missing species, we need to use the charge and mass balance law. That is, the mass should be conserved: the total mass on the left-hand side with respect to the arrow should be equal to the total mass on the right-hand side with respect to the arrow:

238 = 234 + A

Notice from here that:

A = 238 - 234 = 4

So far we know that the mass of X is 4. Similarly, we apply the law of charge conservation. The total charge should be conserved:

92=90+Z

From here:

Z = 92-90=2

We have a particle:

\\_{2}^{4} X

Looking at the periodic table, an atom with Z = 2 corresponds to helium. This can also be written as an alpha particle:

\\_{2}^{4} \alpha

5 0
3 years ago
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aliina [53]

Answer:

A.

Explanation:

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