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3 years ago

Ag(No3)+Na3(Po4)+Ag3(Po4)+Na(No3)

Chemistry

1 answer:

musickatia [10]3 years ago

5 0

3AgNO₃ + Na₃PO₄ → Ag₃PO₄ + 3NaNO₃

Explanation:

AgNO₃+Na₃(PO₄) → Ag₃(PO₄) + NaNO₃

To balance this chemical equation, we can adopt a simple mathematical approach through which we can establish simple and solvable algebraic equations.

aAgNO₃ + bNa₃PO₄ → cAg₃PO₄ + dNaNO₃

a, b, c and d are the coefficients needed to balance the equation.

Conserving Ag: a = 3c

N: a = d

O: 2a + 4b = 4c + 2d

Na: 3b = d

P: b = c

let a = 1; d = 1

b = $\frac{1}{3}$

c = $\frac{1}{3}$

Multiplying through by 3:

a = 3, b = 1, c = 1 and d = 3

3AgNO₃ + Na₃PO₄ → Ag₃PO₄ + 3NaNO₃

Learn more:

Balanced equation brainly.com/question/5964324

#learnwithBrainly

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Compare the following sodium atoms in terms of their neutrons and mass numbers 24Na, 23Na

olga_2 [115]

Na-24 and Na-23 have the same number of atoms=11, different neutrons(13 and 12),different mass number(24 and 23)

<h3>Further explanation </h3>

The elements in nature have several types of isotopes

Isotopes have the same number of protons and having a different number of neutrons.

So Isotopes are elements that have the same Atomic Number (Proton)

₁₁²³Na

number of atoms = 11

mass number = 23

number of neutrons=23-11=12

₁₁²⁴Na

number of atoms = 11

mass number = 24

number of neutrons=24-11=13

7 0

3 years ago

How does a bimetallic thermometer works

-BARSIC- [3]

It's made up of two different metals bonded together, which expand by different amounts as they heat up. As the temperature changes, the bimetallic strip curves more or less tightly (contracts or expands) and the pointer, attached to it, moves up or down the scale.

7 0

3 years ago

What fraction of a sample is left after exactly 3 half-lives?

PSYCHO15rus [73]

(1/2)^3 is the fraction of a sample after 3 half lives

5 0

3 years ago

What is the density of an object that has a volume of 26 mL and a mass of 52 g?

Norma-Jean [14]

Answer:

<h2>Density = 2 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

$Density = \frac{mass}{volume}$

From the question

mass = 52 g

volume = 26 mL

Substitute the values into the above formula and solve for the density

That's

$Density = \frac{52}{26}$

We have the final answer as

<h3>Density = 2 g/mL</h3>

Hope this helps you

4 0

3 years ago

1. 2Al(s) + 3H2SO4(aq) → Al2(SO4)3(aq) + 3H2(g) a. Determine the volume (mL) of 15.0 M sulfuric acid needed to react with 45.0 g

QveST [7]

Answer:

a. 167 mL b. 39.27 %

Explanation:

a. From the chemical equation. 2 mole of Al reacts with 3 mole H₂SO₄ to produce 1 mol Al₂(SO₄)₃.

Now, we calculate the number of moles of Al in 45.0 g Al.

We know number of moles, n = m/M where m = mass of Al = 45.0 g and M = molar mass of Al = 26.98 g/mol.

So n = 45.0 g/26.98 g/mol = 1.668 mol

Since 2 mole of Al reacts with 3 mole H₂SO₄, then 1.668 mole of Al reacts with x mole H₂SO₄. So, x = 3 × 1.668/2 mol = 2.5 mol

So, we have 2.5 mol H₂SO₄.

Now number of moles of H₂SO₄, n = CV where C = concentration of H₂SO₄ = 15.0 M = 15.0 mol/L and V = volume of H₂SO₄.

V = n/C

= 2.5 mol/15.0 mol/L

= 0.167 L

= 167 mL of 15.0 M H₂SO₄ reacts with 45.0 g Al to produce aluminum sulfate.

b. From the chemical reaction, 2 mol Al produces 1 mol Al₂(SO₄)₃

Therefore 1.668 mol Al will produce x mol Al₂(SO₄)₃. So, x = 1 mol × 1.668 mol/2 mol = 0.834 mol

So, we need to find the mass of 0.834 mol Al₂(SO₄)₃. Now molar mass Al₂(SO₄)₃ = 2 × 26.98 g/mol + 3 × 32 g/mol + 4 × 3 × 16 g/mol = 53.96 g/mol + 96 g/mol + 192 g/mol = 341.96 g/mol.

Also number of moles of Al₂(SO₄)₃, n = mass of Al₂(SO₄)₃,m/molar mass Al₂(SO₄)₃, M

n =m/M

So, m = nM = 0.834 mol × 341.96 g/mol = 285.2 g

% yield = Actual yield/theoretical yield × 100 %

Actual yield = 112 g, /theoretical yield = 285.2 g

So, % yield = 112 g/285.2 g × 100 %

= 0.3927 × 100 %

= 39.27 %

8 0

2 years ago