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8_murik_8 [283]
2 years ago
14

Why does radiation decrease over time?

Chemistry
1 answer:
Aleksandr-060686 [28]2 years ago
8 0

Radiation decrease over time due to the concentration of radioactive atoms and the concentration decreases as radioactive particles are emitted (Option D).

<h3>What is radiation?</h3>

Radiation refers to the transmission of energy by means of subatomic particles that travel as waves.

Radioactive isotopes are also known as radioisotopes, which have unstable combinations of subatomic particles (i.e., neutrons or protons) in their atomic nuclei, and thus may emit alpha particles, gamma rays or beta particles.

Radioactive isotopes such as C14 lost (emit) energy per unit of time, which is known as radiation or radioactive decay.

In conclusion, radiation decrease over time due to the concentration of radioactive atoms and the concentration decreases as radioactive particles are emitted (Option D).

Learn more about radioactive isotopes here:

brainly.com/question/18640165

#SPJ1

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What can you predict about an element from its position in the periodic table?
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How much time will it take a car traveling at an average of 75 mph to go a distance of 225 miles​
mojhsa [17]

Time taken = 3 hours

<h3>Further explanation</h3>

Given

speed : 75 mph

distance : 225 miles

Required

time taken

Solution

An equation of constant velocity motion  

\large {\boxed {\bold {d = v \times \: t}}}

d = distance = m  

v = speed = m / s  

t = time = seconds  

Input the value :

t = d : v

t = 225 miles : 75 miles/hour

t = 3 hours

7 0
3 years ago
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Tpy6a [65]

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Explanation:

5 0
3 years ago
A sample of an unknown metal has a mass of 58.932g. it has been heated to 101.00 degrees C, then dropped quickly into 45.20 mL o
yaroslaw [1]
<h3>Answer:</h3>

0.111 J/g°C

<h3>Explanation:</h3>

We are given;

  • Mass of the unknown metal sample as 58.932 g
  • Initial temperature of the metal sample as 101°C
  • Final temperature of metal is 23.68 °C
  • Volume of pure water = 45.2 mL

But, density of pure water = 1 g/mL

  • Therefore; mass of pure water is 45.2 g
  • Initial temperature of water = 21°C
  • Final temperature of water is 23.68 °C
  • Specific heat capacity of water = 4.184 J/g°C

We are required to determine the specific heat of the metal;

<h3>Step 1: Calculate the amount of heat gained by pure water</h3>

Q = m × c × ΔT

For water, ΔT = 23.68 °C - 21° C

                       = 2.68 °C

Thus;

Q = 45.2 g × 4.184 J/g°C × 2.68°C

    = 506.833 Joules

<h3>Step 2: Heat released by the unknown metal sample</h3>

We know that, Q =  m × c × ΔT

For the unknown metal, ΔT = 101° C - 23.68 °C

                                              = 77.32°C

Assuming the specific heat capacity of the unknown metal is c

Then;

Q = 58.932 g × c × 77.32°C

   = 4556.62c Joules

<h3>Step 3: Calculate the specific heat capacity of the unknown metal sample</h3>
  • We know that, the heat released by the unknown metal sample is equal to the heat gained by the water.
  • Therefore;

4556.62c Joules = 506.833 Joules

c = 506.833 ÷4556.62

  = 0.111 J/g°C

Thus, the specific heat capacity of the unknown metal is 0.111 J/g°C

8 0
3 years ago
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