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horrorfan [7]
3 years ago
14

What is the frequency for the scores in the interval 81-100?

Mathematics
1 answer:
Mrac [35]3 years ago
5 0

I think it should be -19


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A quiz-show contestant is presented with two questions, question 1 and question 2, and she can choose which question to answer f
Mrrafil [7]

Answer:

The contestant should try and answer question 2 first to maximize the expected reward.

Step-by-step explanation:

Let the probability of getting question 1 right = P(A) = 0.60

Probability of not getting question 1 = P(A') = 1 - P(A) = 1 - 0.60 = 0.40

Let the probability of getting question 2 right be = P(B) = 0.80

Probability of not getting question 2 = P(B') = 1 - P(B) = 1 - 0.80 = 0.20

To obtain the better option using the expected value method.

E(X) = Σ xᵢpᵢ

where pᵢ = each probability.

xᵢ = cash reward for each probability.

There are two ways to go about this.

Approach 1

If the contestant attempts question 1 first.

The possible probabilities include

1) The contestant misses the question 1 and cannot answer question 2 = P(A') = 0.40; cash reward associated = $0

2) The contestant gets the question 1 and misses question 2 = P(A n B') = P(A) × P(B') = 0.6 × 0.2 = 0.12; cash reward associated with this probability = $200

3) The contestant gets the question 1 and gets the question 2 too = P(A n B) = P(A) × P(B) = 0.6 × 0.8 = 0.48; cash reward associated with this probability = $300

Expected reward for this approach

E(X) = (0.4×0) + (0.12×200) + (0.48×300) = $168

Approach 2

If the contestant attempts question 2 first.

The possible probabilities include

1) The contestant misses the question 2 and cannot answer question 1 = P(B') = 0.20; cash reward associated = $0

2) The contestant gets the question 2 and misses question 1 = P(A' n B) = P(A') × P(B) = 0.4 × 0.8 = 0.32; cash reward associated with this probability = $100

3) The contestant gets the question 2 and gets the question 1 too = P(A n B) = P(A) × P(B) = 0.6 × 0.8 = 0.48; cash reward associated with this probability = $300

Expected reward for this approach

E(X) = (0.2×0) + (0.32×100) + (0.48×300) = $176

Approach 2 is the better approach to follow as it has a higher expected reward.

The contestant should try and answer question 2 first to maximize the expected reward.

Hope this helps!!!

3 0
3 years ago
A machine paints 34o toy boats im 3/4 of an hour how many boats can he make per hour
leonid [27]
Here, we can set up a proportion:

34 ÷ 3/4 = ? ÷ 1
34*1 = 34
34÷3/4 = the time needed to build one toyboat

34/3/4 = 45.3333333333

45.3 repeating is not a whole number, so we need to approximate. 

45 is the closest whole number, 

So.. a machine can paint 45 toy boats per hour. 

I really hope that helped! :) 

7 0
3 years ago
Sandy sold 22 tickets, which was at least 6 more than twice the number of tickets that Teresa sold. This can be represented by t
iVinArrow [24]

Answer:

7

Step-by-step explanation:

Let 'x' represent the number of tickets that Teresa sold, and x is integer and x>=0 (you can not sell negative number of tickets)

6 + 2x < 22

x < 8

The range of possible number of tickets that Teresa sold is {0, 1, 2, 3, 4, 5, 6, 7}.

7 0
3 years ago
What is the definition of supplementary angles.
never [62]

Answer: either of two angles whose sum is 180°.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
PLEASE HELP! WILL GIVE BRAINLIEST!
VMariaS [17]

Answer:

Answer: the equivalent form of 6(2x+3x+10) are 12x+18x + 60 and 30x+60.

Hope this helps

8 0
3 years ago
Read 2 more answers
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