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STatiana [176]
3 years ago
7

6x-2=7x+9 find x plz help

Mathematics
2 answers:
steposvetlana [31]3 years ago
7 0

Answer:

x=-11

Step-by-step explanation:

6x-2=7x+9

Add 2 to both sides:

6x-2+2=7x+9+2

6x=7x+11

Subtract 7x from both sides:

6x-7x=7x+11-7x

-x=11

Divide both sides by -1:

\frac{-x}{-1}=\frac{11}{-1}

x=-11

SVEN [57.7K]3 years ago
5 0

Answer:

X= -11

Step-by-step explanation:

Simplifying

6x + -2 = 7x + 9

Reorder the terms:

-2 + 6x = 7x + 9

Reorder the terms:

-2 + 6x = 9 + 7x

Solving

-2 + 6x = 9 + 7x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-7x' to each side of the equation.

-2 + 6x + -7x = 9 + 7x + -7x

Combine like terms: 6x + -7x = -1x

-2 + -1x = 9 + 7x + -7x

Combine like terms: 7x + -7x = 0

-2 + -1x = 9 + 0

-2 + -1x = 9

Add '2' to each side of the equation.

-2 + 2 + -1x = 9 + 2

Combine like terms: -2 + 2 = 0

0 + -1x = 9 + 2

-1x = 9 + 2

Combine like terms: 9 + 2 = 11

-1x = 11

Divide each side by '-1'.

x = -11

Simplifying

x = -11

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The total scores on the Medical College Admission Test (MCAT) in 2013 follow a Normal distribution with mean 25.3 and standard d
Elden [556K]
In a normal distribution, the median is the same as the mean (25.3). The first quartile is the value of Q_1 such that

\mathbb P(X

You have

\mathbb P(X

For the standard normal distribution, the first quartile is about z\approx-0.6745, and by symmetry the third quartile would be z\approx0.6745. In terms of the MCAT score distribution, these values are

\dfrac{Q_1-25.3}{6.5}=-0.6745\implies Q_1\approx20.9
\dfrac{Q_3-25.3}{6.5}=0.6745\implies Q_3\approx29.7

The interquartile range (IQR) is just the difference between the two quartiles, so the IQR is about 8.8.

The central 80% of the scores have z-scores \pm z such that

\mathbb P(-z

That leaves 10% on either side of this range, which means

\underbrace{\mathbb P(-z

You have

\mathbb P(Z

Converting to MCAT scores,

-1.2816=\dfrac{x_{\text{low}}-25.3}{6.5}\implies x_{\text{low}}\approx17.0
1.2816=\dfrac{x_{\text{high}}-25.3}{6.5}\implies x_{\text{high}}\approx33.6

So the interval that contains the central 80% is (17.0,33.6) (give or take).
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3 years ago
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anygoal [31]

Answer:

I think it is 24

Step-by-step explanation:

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3×8=24

6 0
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Step-by-step explanation:

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Two solutions:

1. x =(100-√2160)/2=50-6√ 15 = 26.762

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3 years ago
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Step-by-step explanation:

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