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JulijaS [17]
3 years ago
14

I'm not really good at it can you help. ?

Mathematics
1 answer:
Vesnalui [34]3 years ago
5 0
Sure , What Do Youu Need Help With ?
You might be interested in
A star in the sky appears to move by 12 arcseconds over the course of 6 months. Convert this number into first areminutes then d
Bumek [7]

Answer:

Given :A star in the sky appears to move by 12 arc seconds over the course of 6 months.

To Find :Convert this number into first arc minutes then degrees.

Solution:

60 arc seconds = 1 arc minute

1 arc seconds = \frac{1}{60} arc minute

12 arc seconds = \frac{1}{60} \times 12 arc minute

12 arc seconds = \frac{1}{5} arc minute

So, 12 arc seconds = \frac{1}{5} arc minute

Now convert it into degrees

60 arc minute = 1 degree

1 arc minute = \frac{1}{60} degree

\frac{1}{5} arc minute = \frac{1}{60} \times \frac{1}{5} degree

\frac{1}{5} arc minute = \frac{1}{300} degrees

12 arc seconds = \frac{1}{300} degrees

8 0
3 years ago
Please help me with both parts?
Neko [114]
I'm willing to help you with both parts
4 0
3 years ago
What is 0.29 of 200 rounded to the nearest hundred
jekas [21]

Answer:

100

Step-by-step explanation:

<u>Step 1:  Make an expression</u>

<u />200 * 0.29 = x

58 = x

<u>Step 2:  Round</u>

<u />58

100

Answer:  100

3 0
3 years ago
Cards are drawn, one at a time, from a standard deck; each card is replaced before the next one is drawn. Let X be the number of
steposvetlana [31]

Cards are drawn, one at a time, from a standard deck; each card is replaced before the next one is drawn. Let X be the number of draws necessary to get an ace. Find E(X) is given in the following way

Step-by-step explanation:

  • From a standard deck of cards, one card is drawn. What is the probability that the card is black and a jack? P(Black and Jack)  P(Black) = 26/52 or ½ , P(Jack) is 4/52 or 1/13 so P(Black and Jack) = ½ * 1/13 = 1/26
  • A standard deck of cards is shuffled and one card is drawn. Find the probability that the card is a queen or an ace.

P(Q or A) = P(Q) = 4/52 or 1/13 + P(A) = 4/52 or 1/13 = 1/13 + 1/13 = 2/13

  • WITHOUT REPLACEMENT: If you draw two cards from the deck without replacement, what is the  probability that they will both be aces?

P(AA) = (4/52)(3/51) = 1/221.

  • WITHOUT REPLACEMENT: What is the probability that the second card will be an ace if the first card is a  king?

P(A|K) = 4/51 since there are four aces in the deck but only 51 cards left after the king has been  removed.

  • WITH REPLACEMENT: Find the probability of drawing three queens in a row, with replacement. We pick  a card, write down what it is, then put it back in the deck and draw again. To find the P(QQQ), we find the

probability of drawing the first queen which is 4/52.

  • The probability of drawing the second queen is also  4/52 and the third is 4/52.
  • We multiply these three individual probabilities together to get P(QQQ) =
  • P(Q)P(Q)P(Q) = (4/52)(4/52)(4/52) = .00004 which is very small but not impossible.
  • Probability of getting a royal flush = P(10 and Jack and Queen and King and Ace of the same suit)
5 0
3 years ago
What is W when 4w-18&gt;10
Degger [83]

Answer:

Inequality of W would be w>7

Step-by-step explanation:

Isolate the variable by dividing each side by factors that do not contain the variable. <em>Hope this helps.</em>

4w-18>10

4w>28 [Moved +18 over]

4w>7 [28 divided by 4]

8 0
3 years ago
Read 2 more answers
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