Answer:
inches: 0 and 7
Step-by-step explanation:
because you are subtracting by 1
Answer: 20 Decibels
Step-by-step explanation:
I don't know
Answer:
B. x < -8 or x > 8
Step-by-step explanation:
You can use process of elimination to solve this problem by going through every solution and testing them out, but let's jump right to B.
Process:
You know that since the inequality states that x^2 has to be greater than 64, x has to be more than 8, or less than -8.
This is because 8^2 = 64, and -8^2 = 64, and the inequality requires the answer to be more than 64.
Looking at B., you can see that if x is < -8, the square of, for example, -9, would be 81. This is greater than 64, so this works!
Now, B. also has an alternative. The 'or' is a major clue to which is the correct answer, since the square root of any number can be positive or negative. (-8^2 = 8^2)
The 'or' states that x must be greater than 8. So, for example, if we take the square of 10, we get 100, and that is also greater than 64.
We've proven that this solution is accurate for both parts, so it is definitely the one we want!
Hope this helps!
Answer:
The distance between the walls is 70 m.
Step-by-step explanation:
Given: A source of laser light is at point A on the ground between two parallel walls BE and CD . The walls are perpendicular to the ground that is
BE ⊥ ED and CD ⊥ ED
AB is a ray of light which strikes the wall on the left at point B which is 30 meters above the ground. that is BE = 30 m
AC is a ray of light which strikes the wall on the right at point C. The length of AC = 80 meters.
The ray AB makes an angle of 45 degrees with the ground that is m∠BAE = 45°
The ray AC makes an angle of 60 degrees with the ground that is m∠CAD = 60°
As shown is figure attached below.
WE have to find the distance between the walls that is Length of ED
Length of ED = EA + AD
Consider the Δ AEB,
Using trigonometric ratio,

Here
, perpendicular = 30 m and base we can find.
thus,

We know 
thus, EA = 30 m
Consider the Δ AEB,
Using trigonometric ratio,

Here
, hypotenuse = 80 m and base we can find.
thus, 
We know, 
thus, Base = 40 m
AD = 40 m
Thus, the distance between the walls that is the length of ED = 30 + 40 = 70 m
1) Given
2) Adding segments AB and BC together gives AC (Addition postulate, not too sure about the terminology)
3) Segment Addition postulate
4) Segment Addition postulate(Knowing that AC=BD, the distance between BC and CD add up to BD, shown in #3. AB and BC add together to give AC)
5) Subtraction property of Equality
Hope I helped :)