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3 years ago

Light waves from the sun can be converted to electricity through __________.

Physics

1 answer:

ddd [48]3 years ago

3 0

Answer:

light waves can be converted to electricity through <em>a solar cell</em>

Explanation:

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A spherical capacitor is formed from two concentric spherical conducting shells separated by vacuum. The inner sphere has a radi

Svetlanka [38]

Answer: a) 73.41 10^-12 F; b)4.83* 10^3 N/C; c) 3.66 *10^3 N/C

Explanation: To solve this problem we have to consider the following: The Capacity= Charge/Potential Difference

As we know the capacity is value that depend on the geometry of the capacitor, in our case two concentric spheres.

So Potential Difference between the spheres is given by:

ΔV=- $\int\limits^a_b {E} \, dx$

Where E = k*Q/ r^2

so we have $\int\limits^a_b {K+Q1/r} \, dr$

then

Vb-Va=k*Q(1/b-1/a)=kQ (ab/b-a)

Finally using C=Q/ΔV=ab/(k(b-a))

To caclulate the electric firld we first obtain the charge

Q=ΔV*C=120 V*73.41 10^-12 F=8.8 10^-9 C

so E=KQ/r^2 for both values of r

r=12.8 cm ( in meters)

r2=14.7 cm

E(r1)=4.83* 10^3 N/C

E(r2)=3.66 *10^3 N/C

8 0

3 years ago

A ball is launched vertically with an initial speed of y˙0= 50 m/s, and its acceleration is governed by y¨=-g-cDy˙2, where the a

stira [4]

Answer:

Explanation:

Given

acceleration is given by

$a=-g-c_Dv^2$

where $\ddot{y}=a$

$\dot{y}=v$

Also acceleration is given by

$a=v\frac{\mathrm{d} v}{\mathrm{d} s}$

$ds=\frac{v}{a}dv$

$\int ds=\int \frac{v}{-g-0.001v^2}dv$

$\Rightarrow Let -g-0.001v^2=t$

$-0.001\times 2vdv=dt$

$vdv=-\frac{dt}{0.002}$

$at\ v_0=50\ m/s,\ t=-g-0.001(50)^2$

$t=-g-2.5$

at $v=0,\ t=-g$

$\int_{0}^{s}ds=\int_{-g}^{-g-2.5}\frac{-dt}{0.002t}$

$\int_{0}^{s}ds=\int^{-g}_{-g-2.5}\frac{dt}{0.002t}$

$s=\frac{1}{0.002}lnt|_{-g}^{-g-2.5}$

$s=\frac{1}{0.002}\ln (\frac{g+2.5}{g})$

$s=113.608\ m$

when air drag is neglected maximum height reached is

$h=\frac{v_0^2}{2g}$

$h=\frac{50^2}{2\times 9.8}$

$h=127.55\ m$

3 0

3 years ago

A clothes dryer in a home draws a current of 10 amps when connected on a special 220-volts household circuit.what is the resista

aliya0001 [1]

Answer:

22Ω

Explanation:

if V ⇒ voltage

I ⇒ current

R ⇒ resistance

V = IR

220 = 10 x R

220 / 10 = R

22 = R

8 0

2 years ago

Despite the gases, dust, and stars that compose the universe, it is still mostly made up of ____________________.

ivann1987 [24]

Answer:

space

Explanation:

5 0

3 years ago

A beam of protons is moving toward a target in a particle accelerator. This beam constitutes a current whose value is. (a) How m

Gelneren [198K]

Answer:

a. 5 × 10¹⁹ protons b. 2.05 × 10⁷ °C

Explanation:

Here is the complete question

A beam of protons is moving toward a target in a particle accelerator. This beam constitutes a current whose value is 0.42 A. (a) How many protons strike the target in 19 seconds? (b) Each proton has a kinetic energy of 6.0 x 10-12 J. Suppose the target is a 17-gram block of metal whose specific heat capacity is 860 J/(kg Co), and all the kinetic energy of the protons goes into heating it up. What is the change in temperature of the block at the end of 19 s?

Solution

i = Q/t = ne/t

n = it/e where i = current = 0.42 A, n = number of protons, e = proton charge = 1.602 × 10⁻¹⁹ C and t = time = 19 s

So n = 0.42 A × 19 s/1.602 × 10⁻¹⁹ C

= 4.98 × 10¹⁹ protons

≅ 5 × 10¹⁹ protons

The total kinetic energy of the protons = heat change of target

total kinetic energy of the protons = n × kinetic energy per proton

= 5 × 10¹⁹ protons × 6.0 × 10⁻¹² J per proton

= 30 × 10⁷ J

heat change of target = Q = mcΔT ⇒ ΔT = Q/mc where m = mass of block = 17 g = 0.017 kg and c = specific heat capacity = 860 J/(kg °C)

ΔT = Q/mc = 30 × 10⁷ J/0.017 kg × 860 J/(kg °C)

= 30 × 10⁷/14.62

= 2.05 × 10⁷ °C

5 0

3 years ago