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Leni [432]
3 years ago
13

Astronauts on the first trip to Mars take along a simple pendulum that has a period on earth of 1.80 s . The period on Mars turn

s out to be 2.94 s . How long is the pendulum?What is the Martian acceleration due to gravity?
Physics
1 answer:
kogti [31]3 years ago
8 0

Answer:

l = 0.8 m

gMars = 3.65 m/s2

Explanation:

The period of a pendulum depends on the length of it and the acceleration of gravity according to this equation:

T = 2 \pi  \sqrt{\frac{l}{g}}

If the pendulum has a period of 1.8s on Earth, the length must be:

l = g * (\frac{T}{2\pi})^2 = 9.81 * (\frac{1.8}{2\pi})^2 = 0.8 m

If it has a period of 2.94 s on Mars, the gravity must be:

g = \frac{l}{(\frac{T}{2\pi})^2} = \frac{4 \pi^2 l}{T^2} = \frac{4 \pi^2 * 0.8}{2.94^2} = 3.65 \frac{m}{s^2}

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Answer:

-  path differnce = 2.18*10^-6

-  1538 lines

Explanation:

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path\ difference\ = dsin\theta           (1)

d: separation between slits = 0.50mm = 0.50*10^-3 m

θ: angle of a diffraction = 0.25°

Then, the path difference is:

path\ difference\ =(0.50*10^{-3}m)sin(0.25\°)=2.18*10^{-6}m

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The maxium number of bright lines are twice the previous result, that is, 1538 lines

8 0
3 years ago
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The acceleration due to gravity is 9.81 m/s2, towards the Earth. Rain falling from an altitude of 9,000 m would fall for about 1
Anna [14]

Answer:

the final speed of the rain is 541 m/s.

Explanation:

Given;

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height of fall of the rain, h = 9,000 m

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The final speed of the rain is calculated as;

v^2 = u^2 + 2gh\\\\v^2 = (-341)^2 + 2(9.8\times 9000)\\\\v^2 = 292681\\\\v = \sqrt{292681} \\\\v = 541 \ m/s

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4 years ago
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