Answer:
v = 10 m/s
Explanation:
Let's assume the wheel does not slip as it accelerates.
Energy theory is more straightforward than kinematics in my opinion.
Work done on the wheel
W = Fd = 45(12) = 540 J
Some is converted to potential energy
PE = mgh = 4(9.8)12sin30 = 235.2 J
As there is no friction mentioned, the remainder is kinetic energy
KE = 540 - 235.2 = 304.8 J
KE = ½mv² + ½Iω²
ω = v/R
KE = ½mv² + ½I(v/R)² = ½(m + I/R²)v²
v = √(2KE / (m + I/R²))
v = √(2(304.8) / (4 + 0.5/0.5²)) = √101.6
v = 10.07968...
Momentum of the object can be calculated by multiplying the mass of the object and the velocity of the moving object. In this case, the starting situation should be the object should be moving, else there is no velocity and thus momentum is equal to zero .Answer is C
If the acceleration is constant, and the starting velocity is zero, the relationship between the acceleration of a falling body (a), the time it takes to fall (t), and instantaneous velocity when it hits the ground (v) is:
the general equation of acceleration is:
vf = vi + at
assuming the initial velocity (vi) is zero, the equation becomes:
vf = at
v = at
Answer:
The magnitude and algebraic sign of q is 
Explanation:
Given that,
Point charge = -0.70 μC[/tex]
We need to calculate the force for all charges
The electric force at first corner
The electric force at opposite corner
The net force is
Put the value into the formula
The electric force at second corner
The net force acting on either of the charges is zero.
So, 
Hence, The magnitude and algebraic sign of q is
Answer:
It takes more force to accelerate a dump truck
Explanation:
Because a dump truck has more mass so it would also have more friction and accelerate slower.
