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oksano4ka [1.4K]
4 years ago
15

Which term describes when situations, events, or people make demands on your body and mind

Physics
2 answers:
pishuonlain [190]4 years ago
7 0

stress is the correct answer to this problem


mars1129 [50]4 years ago
6 0
<span>Stress
       
Stress is a condition of mental strain or pressure on the body and coming about because of unfavorable or demanding conditions that the person cannot handle at that moment.</span>
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Why are watersheds useful?
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Watersheds provide many of us with our drinking water supply, plus recreational opportunities and aesthetic beauty. Watersheds are areas from which water runs into a public water supply. Thus, much of the water you drink from a public source has passed through a watershed. Because of this, it's important that care be taken to minimize any contaminents that may find their way into a public water supply. A small example of a watershed would be the hills around a reservoir. A larger example would be the portions of Pennsylvania, New York, Virginia, Maryland, Delaware and Washington DC that are designated Chesapeake Bay watershed.

8 0
3 years ago
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When light reflects on a mirror, does it undergo a phase change?
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The light does not undergo a phase change.

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5 0
3 years ago
Gravity is the strongest non-contact force on Earth.<br><br> a. true <br> b. false
Semmy [17]

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6 0
3 years ago
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A 1.0 kg mass attached to a spring is pulled back horizontally across a table so that the potential energy of the system is incr
saw5 [17]
-- If it's all happening horizontally, then gravity is not involved. 
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3 0
3 years ago
A 0.305 kg book rests at an angle against one side of a bookshelf. The magnitude and direction of the total force exerted on the
tankabanditka [31]

Answer

given,

F_L= 1.52\ N

\theta_L= 31^0

mass of book = 0.305 Kg

so, from the diagram attached  below

F_L cos {\theta_L} + F_b sin {\theta_b} = m g

1.52 times cos {31^0} + F_b sin {\theta_b} = 0.305 \times 9.8

F_b sin {\theta_b} = 2.989 -1.303

F_b sin {\theta_b} = 1.686

computing horizontal component

F_b cos {\theta_b} = F_L sin {\theta_L}

cos {\theta_b} = \dfrac{F_L sin {\theta_L}}{F_b}

cos {\theta_b} = \dfrac{1.52 \times sin {31^0}}{1.686}

cos {\theta_b} = 0.464

θ = 62.35°

5 0
4 years ago
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