2 years ago

What is the expermintal example of Zeeman effect?

Physics

1 answer:

Mrac [35]2 years ago

6 0

Answer:

When the spectral lines are absorption lines, the effect is called inverse Zeeman effect.

You might be interested in

What is 800,000,000 meters in scientific notation

Paladinen [302]

8 x 10^8 = 800,000,000

In Scientific Notation, your goal is to get your the number you're multiplying by 10 (8 in this case) to be between 0 and 10. Therefore, you would NOT have 80 x 10^7 because 80 is not between 0 and 10.

7 0

3 years ago

Read 2 more answers

With manual transmission, use your right foot for the brake and accelerator and left foot for the clutch true or false

GaryK [48]

This is true!

Hope this helps!

4 0

3 years ago

Read 2 more answers

How does the atmosphere’s interaction with different wavelengths of light help to protect life on earth?

marishachu [46]

Answer:

Ozone layer in the upper atmosphere filters most of the harmful radiations of shorter wavelength. It actually absorbs the hazardous radiations like ultraviolet, gamma rays, x- rays and most of all those having shorter wavelength then the visible light. That's how the earth's atmosphere protects life on earth. But unfortunately, climate change and global warming is causing the depletion of ozone layer which is causing skin related diseases and harming not only the human life but also the plants and animals.

4 0

2 years ago

Please help

iVinArrow [24]

Answer is 4,400,000 kg • m/s

4 0

2 years ago

A 3.0-kg mass and a 5.0-kg mass hang vertically at the opposite ends of a rope that goes over an ideal pulley. If the masses are

irga5000 [103]

Answer:

The time taken will be 0.553 seconds.

Explanation:

We should start off by finding the force exerted by the rope on the 3kg weight in this case.

Weight of 5kg mass = 5 * 9.81 = 49.05 N

Weight of 3kg mass = 3 * 9.81 = 29.43 N

The force acting upward on the 3kg mass will equal the weight of the 5kg mass. Thus the resultant force acting on the 3kg mass is:

Total force = 49.05 - 29.43 = 19.62 N (upwards)

We can now find the acceleration:

F = m * a

19.62 = 3 * a

a = 6.54 m/s^2

We now use the following equation of motion to get the time taken to travel 1 meter:

$s=u*t+\frac{1}{2} (a*t^2)$

$1=0*t+\frac{1}{2} (6.54*t^2)$

t = 0.553 seconds

4 0

3 years ago