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kykrilka [37]
3 years ago
6

on a map the distance between two historical markers in 4.5 in in 2.5 in inches represents 10 mi what is the actual distance bet

ween the historical markers
Mathematics
2 answers:
mihalych1998 [28]3 years ago
7 0

Answer:the actual answer is 18 miles. I just did the test

Step-by-step explanation:

Zarrin [17]3 years ago
5 0

Answer:

The actual distance is 16 miles.

Step-by-step explanation:

In order to find this, create a proportion. On the left you should put the scale factor. On the right you should put the markers.

2.5in/10mi = 4.5in/xmi

Now cross multiply to solve.

10mi * 4.5in = 2.5in * xmi

45 = 2.5x

16 mi = x

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For the functions f(x)=4x−3 and g(x)=3x2+4x, find (f∘g)(x) and (g∘f)(x).
barxatty [35]

Answer:

(16x + 21) and (16x - 6)

Step-by-step explanation:

f(g(x)) = f(6 + 4x)

Applying the f(x) function on (6 + 4x) gives

4(6 + 4x) - 3

Which equals 16x + 24 - 3

= 16x + 21

g(f(x)) = g(4x - 3)

Applying the g(x) function on (4x - 3) gives

6 + 4(4x - 3)

Which equals 6 + 16x - 12

= 16x - 6

7 0
3 years ago
a fishbowl shaped like a sphere is filled with water. The fishbowl has a diameter of 16 inches. Which measurement is closest to
gregori [183]

Answer:

The volume of the water in the fishbowl is equal to

(682\frac{2}{3})\pi\ in^{3}  or  2,144.6\ in^{3}

Step-by-step explanation:

we know that

The volume of the sphere (a fishbowl) is equal to

V=\frac{4}{3}\pi r^{3}

In this problem we have

r=16/2=8\ in ----> the radius is half the diameter

substitute

V=\frac{4}{3}\pi (8^{3})=\frac{2,048}{3}\pi\ in^{3}

convert to mixed number

\frac{2,048}{3}\pi\ in^{3}=\pi (\frac{2,046}{3}+\frac{2}{3})=(682\frac{2}{3})\pi\ in^{3}

(3.14156)*(682\frac{2}{3})=2,144.6\ in^{3}

6 0
3 years ago
Read 2 more answers
Need help with problem number 6 please
butalik [34]
So to get the sides you need to cube them
(192)^1/3---->5.769
(375)^1/3---->7.21125
7.21125-5.769= 1.44225
3^(1/3)= 1.44225

Answer: A



3 0
3 years ago
The endpoints of are E(xE , yE) and F(xF , yF). What are the coordinates of the midpoint of ?
Masteriza [31]

Answer:

(\frac{x_e+x_f}{2} , \frac{y_e+y_f}{2})

Step-by-step explanation:

the coordinates of midpoint is average of x value of endpoints and average of y value of endpoints

8 0
4 years ago
I WILL GIVE BRAINLIEST TO WHOEVER IS CORRECT
fredd [130]
Here you go!! It's always best to graph these questions, if you have graph paper near.
If not there are online graphing websites to use!! :))

ANSWER: Choice D (4th answer)

7 0
3 years ago
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