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Setler [38]
3 years ago
8

whenever a chemical is dispensed from its original container into a secondary container the secondary container must be labeled

to show the product name and information true or false
Chemistry
1 answer:
spayn [35]3 years ago
7 0
The answer to this question is true.

If you remove a liquid from its container to a new container, you should put the product name so you will know what is the liquid inside the container.
If you don't do this, you might find a container with unknown liquid. It will be hard to determine what substance inside the container just by observing it. If it dangerous it might harm the others too.
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1. Phosphorous reacts with bromine to form phosphorous tribromide. If 35.0 grams of bromine
Anastaziya [24]

Answer:

70.6 %

Explanation:

First step, we define the reaction:

2P + 3Br₂  →  2PBr₃

We determine the moles of reactant:

35 g . 1mol / 159.8 g = 0.219 moles

We assume, the P is in excess, so the bromine is the limiting reagent.

3 moles of Br₂ can produce 2 moles of phophorous tribromide

Then, 0.219 moles may produce (0.219 . 2) /3 = 0.146 moles of PBr₃

We convert moles to mass:

0.146 mol .  270.67 g /mol = 39.5 g

That's the 100 % yield reaction, also called theoretical yield. The way to determine the % yield is:

(Yield produced / Thoeretical yield) . 100

(27.9 / 39.5) . 100 = 70.6 %

7 0
3 years ago
How many atoms are in 25.0 moles of calcium (Ca)?
arsen [322]

Answer:

1.8066e+24 is the answer

3 0
3 years ago
What is meant by the term chemical reaction​
pantera1 [17]

Answer:

<h3>\huge{ \underline{ \underline { \bold{ \sf{ \orange{See \: below}}}}}}</h3>

Explanation:

▪️\underline{ \bold{ \sf{ \blue{Chemical \: reaction}}}}

⇒The composition , decomposition or displacement of molecules of matter during chemical change is called chemical reaction.

▪️\underline{ \bold{ \sf{ \purple{ \: Further \: more \: explanation}}}}

Various conditions bring about these changes. The chemical reactions are represented by chemicalequation. The compounds or elements that take part in chemical reaction are called reactant. They are written at the left side of an arrow that represent a change while the compound or elements that formed after the chemical change are called product. They are written at the right side of the arrow.

▪️\underline{ \bold{ \sf{ \purple{For \: example}}}}

When nitrogen reacts with hydrogen to form ammonia :

Nitrogen + Hydrogen ⇒ Ammonia

N₂ + 3H₂ ⇒ 2NH₃

<u>Presentation </u><u>of </u><u>a </u><u>chemical </u><u>reaction </u><u>in </u><u>the </u><u>form </u><u>of </u><u>equation </u><u>is </u><u>called </u><u>chemical </u><u>equation </u>. <u>Chemical equation may be word equations or formula equations.</u>

Hope I helped!

Best regards!!

3 0
2 years ago
Consider the reaction between iodine gas and chlorine gas to form iodine monochloride. A reaction mixture at 298.15k initially c
uranmaximum [27]

Step 1 : Write balanced chemical equation

The balanced chemical equation for the reaction between iodine gas and chlorine gas is given below.

I_{2}  (g) + Cl_{2}  (g) ----->  2 ICl (g)

Step 2 : Set up ICE table

We will set up an ICE table for the above reaction

Following points are considered while drawing ICE table

- The initial concentration of product is assumed as 0

- The change in concentration (C) is assumed as x. Change (x) is negative for reactants and positive for products

- The coefficients in balanced equation are considered while writing C values

Check attached file for ICE table

Step 3 : Set up equilibrium constant equation

The equation for equilibrium constant can be written as

K_{eq} = \frac{[ICl]^{2}}{[I_{2}][Cl_{2}]}

Step 4 : Solving for x

Keq at 298.15 K is given as 81.9

Let us plug in the equilibrium values (E) for I₂, Cl₂ and ICl from ICE table

81.9 = \frac{(2x)^{2}}{(0.437-x) (0.269-x)}

81.9 = \frac{(2x)^{2}}{x^{2} -0.706x + 0.118}

(2x)^{2} = 81.9 [ x^{2} -0.706x + 0.118]

4x^{2} = 81.9x^{2} -57.8x +9.66

77.9x^{2} -57.8x+9.66 = 0

Solving the above equation using quadratic formula we get

x = 0.488 or x = 0.254

The value 0.488 cannot be used because the change (C) cannot be greater that initial concentration of the reactants.

Therefore the change in concentration of the gases during the reaction is 0.254 M

Hence, x = 0.254 M

From the ICE table, we know that the equilibrium concentration of ICl is 2x

[ICl]_{eq} = 2 ( 0.254) = 0.508 M

The concentration of ICl when the reaction reaches equilibrium is 0.508 M

6 0
3 years ago
What sequence of enzymes allows for the synthesis of glycogen from glucose-6-phosphate?
Nutka1998 [239]

Answer:

The answer is (e) : phosphoglucomutase, UDP-glucose pyrophosphorylase, glycogen synthase then amylo-(1,4-1,6)-transglycosylase.

Explanation:

Phosphoglucomutase: Convert glucose-6-phosphate to glucose-1-phosphate.

UDP-glucose pyrophosphorylase:  Form UDP-glucose from glucose-1-phosphate.

Glycogen synthase: Add the new glucose from UDP-glucose to the growing glycogen chain.

Amylo-(1,4-1,6)-transglycosylase: This is a branching enzyme, it initiates formation of branches evolving from the main chain.

4 0
3 years ago
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