Protons:
- Have a mass
- Positively charged
- Found inside the nucleus of an atom
Electrons:
- Have a mass. (9.10938188×10−31 kilograms), though this can sometimes be considered negligible due to how small that actually is. Barely factored into atomic mass
- Negatively charged
- Found outside the nucleus in the electron shell
Neutrons:
- Have a mass
- Neutral (no charge)
- Found inside the nucleus of an atom
Atom A:
- 1 proton
- 0 Neutrons
- 1 electron
- Atomic mass of 1
- Atomic number of 1
Atom B:
- 8 Protons
- 10 Neutrons
- 8 electrons
- Atomic mass of 18
- Atomic number of 8
Atomic mass includes the number of protons and neutrons in the nucleus. Atomic number is the number of protons, as this is what defines what type of element the atom is.
Answer:
Ca has the greater Ionization Energy because the Trend is I/e decreases as you move down a group. Therefore, Ca has the greater I/e
Explanation:
His measurements are precise since his pH values are close to each other in a way that it was repeated in all measurements. On the contrary to accuracy, it is the closeness to the actual pH value he should have achieved. Therefore, Jose's results are precise but not accurate since his value is not close to the actual value of pH 4.
Answer:
See explanation below
Explanation:
First, we need to understand that the monochlorination of an alkane like this one, involves substitution of one of the atoms of hydrogen of the molecule for an atom of chlorine.
This reaction takes place when the alkane reacts with Cl₂ in presence of light or heat.
When this happens, the first step involves the breaking of the double bond of the chlorine to form the ion Cl⁻.
The next step involves the substraction of the hydrogen of the molecule by the Chlorine. This will leave the alkane with a lone pair available for reaction.
The third step, the alkane with the lone pair of electron substract a chlorine for the beggining and form the mono chlorinated product.
The final step involves forming the remaining products with the remaining reagents there.
In the picture attached you have the mechanism and product for this reaction: