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GREYUIT [131]
3 years ago
10

Calculate the density of a solid substance if a cube measuring 2.54 cm on one side has a mass of 108 g/cm3​

Chemistry
1 answer:
kozerog [31]3 years ago
3 0

Answer:

6.59 g/cm³

Explanation:

Step 1: Given data

  • Side of the cube (s): 2.54 cm
  • Mass of the cube (m): 108 g

Step 2: Calculate the volume of the cube

We will use the following expression.

V = s³ = (2.54 cm)³ = 16.4 cm³

Step 3: Calculate the density of the solid

Density is an intrinsic property, equal to the quotient between the mass and the volume.

ρ = m/V

ρ = 108 g / 16.4 cm³ = 6.59 g/cm³

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What is the MOLAR heat of combustion of methane(CH₄) if 64.00g of methane are burned to heat 75.0 ml of water from 25.00°C to 95
melamori03 [73]

Answer:

-5.51 kJ/mol

Explanation:

Step 1: Calculate the heat required to heat the water.

We use the following expression.

Q = c \times m \times \Delta T

where,

  • c: specific heat capacity
  • m: mass
  • ΔT: change in the temperature

The average density of water is 1 g/mL, so 75.0 mL ≅ 75.0 g.

Q = 4.184J/g.\°C \times 75.0g \times (95.00\°C - 25.00\°C) = 2.20 \times 10^{3} J = 2.20 kJ

Step 2: Calculate the heat released by the methane

According to the law of conservation of energy, the sum of the heat released by the combustion of methane (Qc) and the heat absorbed by the water (Qw) is zero

Qc + Qw = 0

Qc = -Qw = -22.0 kJ

Step 3: Calculate the molar heat of combustion of methane.

The molar mass of methane is 16.04 g/mol. We use this data to find the molar heat of combustion of methane, considering that 22.0 kJ are released by the combustion of 64.00 g of methane.

\frac{-22.0kJ}{64.00g} \times \frac{16.04g}{mol} = -5.51 kJ/mol

8 0
3 years ago
What is the molarity of solution prepared by dissolving 11.75 g of KNO3 in enough water to produce 2.00 L of solution?
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Then, molarity is calculated by dividing the number of moles by the volume of the solution. The answer is therefore 0.058 M. 
3 0
3 years ago
The heavier a gas molecule,
mr_godi [17]

Answer:

4

Explanation:

logic

3 0
3 years ago
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