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3 years ago

What are the representative elements? Where are they located

1 answer:

4 0

The representative elements are elements where the s and p orbitals are filling. The transition elements are elements where the d orbitals (groups 3–11 on the periodic table) are filling, and the inner transition metals are the elements where the f orbitals are filling.

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Which of the following is an example of a model demonstrating that matter is made of particles?I. Switching on a lampII. Dissolv

Serggg [28]

Answer:

dissolving salt in water

4 0

3 years ago

Sodium bicarbonate is reacted with concentrated hydrochloric acid at 37.0 °c and 1.00 atm. The reaction of 6.00 kg of bicarbonat

aleksklad [387]

Answer:

1837.89 Lt

Explanation:

The chemical reaction for this situation is:

NaHCO₃ + HCl → NaCL + H₂O + CO₂ ₍g₎

Where the mola mass we need are:

M NaHCO₃ = 84 g/mol

M CO₂ = 44 g/mol

As we have 6.00 Kg of sodium bicarbonate, then:

6 Kg NaHCO₃ = 71.43 moles of NaHCO₃

Due the stoichiometry of this chemaicl reaction:

1 mol NaHCO₃ = 1 mol CO₂

71.43 moles NaHCO₃ = 71.43 moles CO₂

And considering that CO₂ is an ideal gas, we can use the following formula:

PV=nRT

V = (nRT)/P

n = 71.43 mol

R = 0.083 Ltxatm(molxK)

T = 37°C = 310 K

P = 1 atm

So: V = (71.43x0.083x310)/1

V CO₂ = 1837.89 Lt

4 0

3 years ago

Read 2 more answers

B. if 6.73 g of na2co3 is dissolved in enough water to make 250. ml of solution, what is the molar concentration of sodium carbo

BARSIC [14]

Answer:- $[Na_2CO_3]=0.254M$ , $[Na^+]=0.508 M$ , $[CO_3^2^-]=0.254M$

Solution:- We are asked to calculate the molarity of sodium carbonate solution as well as the sodium and carbonate ions.

Molarity is moles of solute per liter of solution. We have been given with 6.73 grams of sodium carbonate and the volume of solution is 250.mL. Grams are converted to moles and mL are converted to L and finally the moles are divided by liters to get the molarity of sodium carbonate.

Molar mass of sodium carbonate is 105.99 gram per mol. The calculations for the molarity of sodium carbonate are shown below:

$\frac{6.73gNa_2CO_3}{250.mL}(\frac{1mol}{105.99g})(\frac{1000mL}{1L})$

= $0.254MNa_2CO_3$

So, molarity of sodium carbonate solution is 0.254 M.

sodium carbonate dissociate to give the ions as:

$Na_2CO_3(aq)\rightarrow 2Na^+(aq)+CO_3^2^-$

There is 1:2 mol ratio between sodium carbonate and sodium ion. So, the molarity of sodium ion will be two times of sodium carbonate molarity.

$[Na^+]=2(0.254M)$ = 0.508 M

There is 1:1 mol ratio between sodium carbonate and carbonate ion. So, the molarity of carbonate ion will be equal to the molarity of sodium carbonate.

$[CO_3^2^-]=0.254M$

5 0

4 years ago

May someone help me on this

Kamila [148]

Answer:

<h2>The mosquitoes like when its wet and moist than dry temp.</h2>

7 0

3 years ago

Finding the density of solids requires a method of measuring the volume of the solid. If the solid has a regular geometric shape

Eduardwww [97]

Answer:

11 g/cm³

sorry if I got wrong

6 0

3 years ago