<span>(2x + y2)<span>5 heres you answer your so welcome</span></span>
Answer:
all real numbers except ±5.
Step-by-step explanation:
Each function (f(x), g(x)) has a domain that is all real numbers. Their quotient (f(x)/g(x)) must exclude values that make g(x) = 0. The quotient is undefined when the denominator is zero. Those excluded values are x = ±5.
The domain of (f/g)(x) is all real numbers except ±5.
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Of course you recognize x^2 -25 = 0 has solutions x = ±√25 = ±5. You can get there two ways:
- add 25 and take the square root: x^2=25; x=±√25.
- factor the difference of squares and set the factors to zero: (x-5)(x+5)=0 has solutions x-5=0 and x+5=0, that is, x = ±5.
Answer:
solution set is (x,y) = (7,6)
Step-by-step explanation:
solving by substitution method
2x +y=20--------------1
6x-5y=12---------------2
from equation 1, solve for y
2x+y=20
y= 20-2x------equation 3
adding value of y in equation 2
6x-5y=12
6x-5(20-2x)=12
6x-100+10x=12
16x= 12+100
16x= 112
x= 112/16
x=7
adding value of x in equation 3
y= 20-2x
y= 20- 2(7)
y=20-14
y=6
so solution set (x,y) = (7,6)
8*4=32
7*4=28
340÷32=10.625
350÷28=12.5
12.5-10.625= 1.875
Answer:
applying for a credit card
paying taxes
opening a checking account
Step-by-step explanation:
Hope this will help yal'l
