Circle = (x-h)^2 + (y-k)^2 = r^2
Center is (h,k) h = -5, k = 2
Radius is 4, r = 4
(x - -5)^2 + (y - 2)^2 = 4^2
(x + 5)^2 + (y - 2)^2 = 16
Two times the length of the longest edge.
Answer:
a) h'(t)= (6cos3t,-9sin3t,3
cos3t)
b) t=0.93994736+πn/3
c) Magnitude of h(t) is 3 which is a constant, so h(t) lies on a sphere
Step-by-step explanation:
Uh i dont know are you supposed to add or substract multiply or divid use nixed numbers on no mixed numbers