To find average atomic mass, multiply each isotope's atomic mass with its relative abundance and add it all up.
15.012*0.1423 + 16.988*0.3348 + 19.177*0.5229 = 17.851 (5 s.f.)
<h3>
Answer:</h3>
43.5 mL
<h3>
Explanation:</h3>
We are given;
- Molarity of dilute acetic acid is 1.74 M
- Volume of the solution that needs to be prepared is 200 mL
- Molarity of the stock solution 8 M
We are required to determine the volume of acid that must be used.
- We need to know the dilution formula;
- According to the dilution equation;
M1V1 = M2V2
Rearranging the formula;
V1 = M2V2 ÷ M1
= (1.74 M × 200 mL) ÷ 8 M
= 43.5 mL
Therefore, the volume of the concentrated acid that must be added is 43.5 mL
This link might help you!!
https://www.eiu.edu/biology/bio1500/writing_a_lab_report.pdf
Number of atoms = moles of magnesium x 6.02x10^23
= 5x6.02x10^23
= 3.01x10^24 atoms.
Hope this helps!
