She read nine chapters each hour
Answer:
318
Step-by-step explanation:
318 is the required answer
I hope it helped you
So given Figure we need to find total surface area
=Area(ABCD)+Area(BCRQ)+Area(QRSP)+Area(ADSP)+Area(ABQP)+Area(DCRS)
=(AB×BC)+(BC×CR)+(QR×RS)+(AD×DS)+(AB×BQ)+(DC×CR)
From figure,
AB=DC=PQ=SR=9 cm
BQ=CR=AP=DS=11 cm
BC=AD=QR=SP=3 cm
On substituting these values We get
Surface Area=(9×3)+(3×11)+(9×3)+(11×3)+(9×11)+(9×11)
=27+33+27+33+99+99=318
I hope it helped you
Answer:
72
Step-by-step explanation:
The area (A) of a rhombus is calculated as
A =
× d₁ × d₂ (d₁ and d₂ are the diagonals )
The diagonals bisect each other at right angles
d₁ = 2 × 6 = 12
Use the tangent ration in the upper left right triangle and the exact value
tan60° = 
tan60° =
=
=
( multiply both sides by 6 )
opp = 6
, then
d₂ = 2 × 6
= 12
Thus
A =
× 12 × 12
= 6 × 12
= 72
Where is the data chart to answer the questions?
Answer:
wheres the question?
Step-by-step explanation: