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3 years ago

Please solve the following equation.

Mathematics

1 answer:

ANTONII [103]3 years ago

6 0

Answer:

Step-by-step explanation:

Pythagoras theorem

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Since Neil Armstrong was the first person to walk on the. moon, the contrapositive is

Romashka-Z-Leto [24]

Answer:

If nobody walked on the moon, then Neil Armstrong didn't

Step-by-step explanation:

The contrapositive flips the sign of "Neil Armstrong" and the "moon," and also switches their position, so you will switch the hypothesis and conclusion as well

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3 years ago

you find a job that pays $15 per hour after working for one year you will get a 4% raise what will your new raise rate after one

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$15.60
15.00 x .04 is the equation

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3 years ago

Read 2 more answers

In a study relating the degree of warping, in mm, of a copper plate (y) to temperature in °C (x), the following summary statisti

elena-14-01-66 [18.8K]

Answer:

y = 0.3035 + 0.0082x

0.6315 mm

x = 23.9634 °C

Step-by-step explanation:

a. Compute the least-squares line for predicting warping from temperature. Round the answers to four decimal places.

We need to find an equation of the form

y = b + mx

where m is the slope and b the Y-intercept.

The slope m can be computed with the formula

$\bf m=\displaystyle\frac{\displaystyle\sum_{i=1}^n(x_i-\bar x)(y_i-\bar y)}{\displaystyle\sum_{i=1}^n(x_i-\bar x)^2}$

Replacing the values in our formula (we will round at the end of the calculations)

$\bf m=\displaystyle\frac{806.94}{98,775}=0.008169476$

the Y-intercept b is computed with the formula

$\bf b=\bar y-m\bar x$

therefore we have

$\bf b=0.5188-0.008169476*26.36=0.303452613$

and the least-squares line rounded to 4 decimals would be

y = 0.3035 + 0.0082x

b. Predict the warping at a temperature of 40°C. Round the answer to three decimal places.

We simply replace x with 40 to get

y = 0.3035 + 0.0082*40 = 0.6315 mm

c. At what temperature will we predict the warping to be 0.5 mm? Round the answer to two decimal places

Here, we replace y with 0.5 and solve for x

0.5 = 0.3035 + 0.0082x ===> x = (0.5-0.3035)/0.0082 ===>

x = 23.9634 °C

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4 years ago

True or false: A problem is ill-conditioned if its solution is highly sensitive to small changes in the problem data.

marysya [2.9K]

Answer:

True

Step-by-step explanation:

True, a problem is ill-conditioned if its solution is highly sensitive to small changes in the problem data.

However, higher-precision arithmetic will make an ill-conditioned problem better conditioned.

In an ill-conditioned problem, for a small change in the independent variable, there is a large change in the dependent variable.

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3 years ago

Pleaseeeeeeee help 32 points

zlopas [31]

Find out the length of each side. For the slanty sides, you can do this by using the formula

$d = \sqrt{(y2-y1)^{2} +(x2-x1)^{2} }$

For the straight sides (like the one on the bottom and the one on the left), just use simple subtraction.

Add up all 4 sides and you get the perimeter. You should get 20, 15, $5\sqrt{5}$ and $5\sqrt{26}$ . The total is 35 + $5(\sqrt{26} +\sqrt{5} )$ .

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3 years ago