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Andreas93 [3]
2 years ago
8

The Willis Tower in Chicago is about 1454 feet tall a model of it has a scale of 2 inches equals 45 feet how tall is the model

Mathematics
1 answer:
Kitty [74]2 years ago
6 0

Answer:

<u>The model is 64.62 inches of height or 5.39 feet</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Height of the Willis Tower in Chicago = 1,454 feet

Scale of the model = 2 inches : 45 feet height

2. How tall is the height?

For answering that question, we will use the following expression:

Height of the model = Height of the Willis Tower in Chicago/Scale in feet * Scale in inches

Replacing with the real values, we have:

Height of the model = 1,454/45 *2

Height of the model = 32.31 * 2 = 64.62 inches

64.62 inches/12 = 5.39 feet

<u>The model is 64.62 inches of height or 5.39 feet</u>

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Step-by-step explanation:

1.   x-7

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2. y+9

A number increased by nine.

3. 6m/8

The product of six and a number, divided by eight.

4. 3y+5 =20

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2 years ago
A phone manufacturer wants to compete in the touch screen phone market. He understands that the lead product has a battery life
alisha [4.7K]

Answer:

a)

The null hypothesis is H_0: \mu \leq 10

The alternative hypothesis is H_1: \mu > 10

b-1) The value of the test statistic is t = 1.86.

b-2) The p-value is of 0.0348.

Step-by-step explanation:

Question a:

Test if the battery life is more than twice of 5 hours:

Twice of 5 hours = 5*2 = 10 hours.

At the null hypothesis, we test if the battery life is of 10 hours or less, than is:

H_0: \mu \leq 10

At the alternative hypothesis, we test if the battery life is of more than 10 hours, that is:

H_1: \mu > 10

b-1. Calculate the value of the test statistic.

The test statistic is:

We have the standard deviation for the sample, so the t-distribution is used to solve this question

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

10 is tested at the null hypothesis:

This means that \mu = 10

In order to test the claim, a researcher samples 45 units of the new phone and finds that the sample battery life averages 10.5 hours with a sample standard deviation of 1.8 hours.

This means that n = 45, X = 10.5, s = 1.8

Then

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{10.5 - 10}{\frac{1.8}{\sqrt{45}}}

t = 1.86

The value of the test statistic is t = 1.86.

b-2. Find the p-value.

Testing if the mean is more than a value, so a right-tailed test.

Sample of 45, so 45 - 1 = 44 degrees of freedom.

Test statistic t = 1.86.

Using a t-distribution calculator, the p-value is of 0.0348.

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2 years ago
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