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3 years ago

What is the slope of the line that passes through the points (2,-2) and (8,1)?

Mathematics

1 answer:

Scrat [10]3 years ago

5 0

Answer:

1/2

Step-by-step explanation:

The formula for the slope given two points is

m = (y2-y1)/(x2-x1)

= (1--2)/(8-2)

= (1+2)/(8-2)

=3/6

1/2

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If x=-3 and y=-2 <br><br><br> Please help me

Dimas [21]

Answer:

-15

Step-by-step explanation:

(-3)^2 - 3(-3)(-2) + 2(-3)

6 0

3 years ago

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How do you get the slope-intercept form for -2x+3y=15? Please show steps and explain

lukranit [14]

To convert an equation to slope intercept form, you have to isolate the y variable.

-2x + 3y = 15

Add 2x to both sides.

3y = 2x + 15

Divide all terms by 3.

<h3>y = 1.5x + 5 is the original equation in slope-intercept form.</h3>

I hope this answers your question!

8 0

4 years ago

A certain college graduate borrows 7864 dollars to buy a car. The lender charges interest at an annual rate of 13%. Assuming tha

White raven [17]

Answer:

Therefore rate of payment = $ 3145.72

Therefore the rate of interest = =$1573.17

Step-by-step explanation:

Consider A represent the balance at time t.

A(0)=$ 7864.

r=13 % =0.13

Rate payment = $k

The balance rate increases by interest (product of interest rate and current balance) and payment rate.

$\frac{dB}{dt} = rB-k$

$\Rightarrow \frac{dB}{dt} - rB=-k$ .......(1)

To solve the equation ,we have to find out the integrating factor.

Here p(t)= the coefficient of B =-r

The integrating factor $=e^{\int p(t) dt$

$=e^{\int (-r)dt$

$=e^{-rt}$

Multiplying the integrating factor the both sides of equation (1)

$e^{-rt}\frac{dB}{dt} -e^{-rt}rB=-ke^{-rt}$

$\Rightarrow e^{-rt}dB - e^{-rt}rBdt=-ke^{-rt}dt$

Integrating both sides

$\Rightarrow \int e^{-rt}dB -\int e^{-rt}rBdt=\int-ke^{-rt}dt$

$\Rightarrow e^{-rt}B=\frac{-ke^{-rt}}{-r} +C$ [ where C arbitrary constant]

$\Rightarrow B(t)=\frac{k}{r} +Ce^{rt}$

Initial condition B=7864 when t =0

$\therefore 7864= \frac{k}{r} - Ce^0$

$\Rightarrow C= \frac{k}{r} -7864$

Then the general solution is

$B(t)=\frac{k}{r}-( \frac{k}{r}-7864)e^{rt}$

To determine the payment rate, we have to put the value of B(3), r and t in the general solution.

Here B(3)=0, r=0.13 and t=3

$B(3)=0=\frac{k}{0.13}-( \frac{k}{0.13}-7864)e^{0.13\times 3}$

$\Rightarrow- 0.48\frac{k}{0.13} +11614.98=0$

⇒k≈3145.72

Therefore rate of payment = $ 3145.72

Therefore the rate of interest = ${(3145.72×3)-7864}

=$1573.17

4 0

4 years ago

Give the following compound's base name.

kenny6666 [7]

Amswer the first one

3 0

3 years ago

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A pair of parallel lines is cut by a transversal, as shown:

liubo4ka [24]

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8 0

3 years ago