Why is it not reasonable to have a linear trinomial with only one type of letter?

Which expression is equivalent to .02m(n - 5) - .02(m + 10)? A) .02mn - .12m - 0.2 B) .02mn + .12m - 0.2 C) .02mn - .12m + 0.2 D

VikaD [51]

The correct answer is A)<span>.02m(n - 5) - .02(m + 10)</span>

7 0

3 years ago

Read 2 more answers

Sum of two numbers is 42 and their difference is 8 . Find the numbers ?

worty [1.4K]

Answer:

25 and 17

Step-by-step explanation:

25+17=42

25-17=8

7 0

3 years ago

Katrina drinks 0.5 gallons of water per day which expression shows how to find the number of cups of water she drinks in a week

kobusy [5.1K]

Answer:

56 cups of water

Step-by-step explanation:

Katrina drinks 0.5 gallons of water per day

We have 7 days in a week, hence, the number of gallons of water she drinks per week is calculated as:

1 day = 0.5 gallons

7 days = x

Cross Multiply

1 day × x = 7 days × 0.5 gallons

x = 7 days × 0.5 gallons/1 day

x = 3.5 gallons

Note that 16 cups = 1 gallon

The number of cups of water she drinks per week is

1 gallon = 16 cups

3.5 gallons = x

Cross Multiply

1 gallons × x = 3.5 gallons × 16 cups

x = 3.5 gallons × 16 cups/1 gallons

x = 56 cups

Therefore, Katrina drinks 56 cups of water in a week

3 0

3 years ago

there were 18 cans ona shelf. a customer bought 7 cans. then jake put 6 cans on the shelf. how many cans are on the shelf now?

Rainbow [258]

18-7+6=17

17 cans are on the shelf.

3 0

3 years ago

Read 2 more answers

Life Expectancies In a study of the life expectancy of people in a certain geographic region, the mean age at death was years an

Sphinxa [80]

Answer:

The probability that the mean life expectancy of the sample is less than X years is the p-value of $Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$ , in which $\mu$ is the mean life expectancy, $\sigma$ is the standard deviation and n is the size of the sample.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

We have:

Mean $\mu$ , standard deviation $\sigma$ .

Sample of size n:

This means that the z-score is now, by the Central Limit Theorem:

$Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

Find the probability that the mean life expectancy will be less than years.

The probability that the mean life expectancy of the sample is less than X years is the p-value of $Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$ , in which $\mu$ is the mean life expectancy, $\sigma$ is the standard deviation and n is the size of the sample.

8 0

3 years ago