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svp [43]
3 years ago
10

Can I have some tips, tricks, and ideas for dropping an egg 12 feet in the air onto a hard surface without it breaking. It HAS t

o be raw. No jelly or peanut butter, the egg cannot be taped, no plastic or glass, it can not be rubber banded either. No parachutes and it has to be smaller than a soccer or the same size.
Physics
2 answers:
lara [203]3 years ago
7 0
Have it land straight up
Ugo [173]3 years ago
4 0
Ok I Did Something Like This In Science My Idea Get a cardboard box put marshmallows around it put a container like i used a small cereal container i put it in the middle of the box put the egg in the container and surround the egg with marsh mellows and tape the top of my box and it survived 

Hoped this is useful if not im sorry at least i tried :)
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Which of the following is a risk associated with taking performance-enchancing drugs.
Damm [24]

Answer:

The correct answer is All of the above.

Explanation:

7 0
2 years ago
At what rate is soda being sucked out of a cylindrical glass that is 6 in tall and has radius of 2 in? The depth of the soda dec
evablogger [386]

Answer:

The soda is being sucket out at a rate of 3.14 cubic inches/second.

Explanation:

R= 2in

S= π*R²= 12.56 inch²

rate= 0.25 in/sec

rate of soda sucked out= rate* S

rate of soda sucked out=  3.14 inch³/sec

4 0
3 years ago
A passenger in a helicopter traveling upwards at 15 m/s accidentally drops a package out the window. If it takes 15 seconds to r
Alexeev081 [22]

Answer:

The helicopter was 1103.63 meters high when the package was dropped.

Explanation:

We consider positive speed as a downward movement

y: height (m)

t: time (s)

v₀: initial speed (m/s)

Δy = v₀t + \frac{1}{2}gt²

Δy= 15\frac{m}{s}×15 s + \frac{1}{2}×9.81\frac{m}{s^{2} }×(15 s)²

Δy= 1103.63 m

8 0
2 years ago
The acceleration due to gravity on the surface of Mars is about one-third the acceleration due to gravity on Earth’s surface.
aksik [14]

Answer:

one-third of its weight on Earth's surface

Explanation:

Weight of an object is = W = m*g

Gravity on Earth = g₁ = 9.8 m/s

Gravity on Mars = g₂ = \frac{1}{3} g₁

Weight of probe on earth = w₁ = m * g₁

Weight of probe on Mars = w₂ = m * g₂ -------- ( 1 )

As g₂ = g₁/3 --------- ( 2 )

Put equation (2) in equation (1)

so

Weight of probe on Mars = w₂ = m * g₁ /3

Weight of probe on Mars = \frac{1}{3}  m * g₁ = \frac{1}{3} w₁

⇒Weight of probe on Mars =\frac{1}{3} Weight of probe on earth

6 0
3 years ago
A train travels 70 kilometers in 1 hours, and then 63 kilometers in 2 hours. What is its average speed?
lozanna [386]
The answer is:  " 44 \frac{1}{3} km " ; 
                              or; write as:  " 44.333 km " .
___________________________________________________________
Explanation:
___________________________________________________________
(70 km + 63 km) ÷ (2 + 1 ) =  133 km ÷ 3 =  " 44 \frac{1}{3} km "  ; 
                                                                            or; write as:  " 44.333 km " .
___________________________________________________________
3 0
3 years ago
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