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MatroZZZ [7]
3 years ago
11

State the Newton's first law of motion in words and in mathematical form.

Physics
1 answer:
Effectus [21]3 years ago
5 0

<em>Newton's First Law</em>

<em>*</em><em> </em><em>Newton's First Law of Motion states that a body will remain at rest or will continue to move at a constant velocity, unless an external force is applied.</em>

<em>*</em><em> </em><em>This means that in order for the acceleration of a body to change, there must be a net force applied to the body. Put another way, if the forces on an object balance, there will be no acceleration (the object will continue at the same speed).So, if we are told that a body is not accelerating (i.e. if it is moving at a constant velocity), we know that the resultant (overall) force in any one direction will be zero.</em>

<em>*</em><em> </em><em> </em><em>I</em><em>t</em><em>s</em><em> </em><em>a</em><em>n</em><em> </em><em>u</em><em>n</em><em>b</em><em>a</em><em>l</em><em>a</em><em>n</em><em>c</em><em>e</em><em>d</em><em> </em><em>f</em><em>o</em><em>r</em><em>c</em><em>e</em><em>,</em>

<em> </em><em>8</em><em>N</em><em> </em><em>a</em><em>c</em><em>t</em><em>i</em><em>n</em><em>g</em><em> </em><em>t</em><em>o</em><em>w</em><em>a</em><em>r</em><em>d</em><em>s</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>l</em><em>e</em><em>f</em><em>t</em><em>,</em><em> </em><em>a</em><em>n</em><em>d</em><em> </em><em>2</em><em>0</em><em>N</em><em> </em><em>a</em><em>c</em><em>t</em><em>i</em><em>n</em><em>g</em><em> </em><em>t</em><em>o</em><em>w</em><em>a</em><em>r</em><em>d</em><em>s</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>r</em><em>i</em><em>g</em><em>h</em><em>t</em><em>.</em>

<em>F</em><em> </em><em>=</em><em> </em><em>F</em><em>2</em><em> </em><em>-</em><em> </em><em>F</em><em>1</em>

<em>=</em><em> </em><em>2</em><em>0</em><em>N</em><em> </em><em>-</em><em> </em><em>8</em><em>N</em>

<em>=</em><em> </em><em>1</em><em>2</em><em>N</em>

<em>F</em><em> </em><em>=</em><em> </em><em>m</em><em>a</em>

<em>a</em><em> </em><em>=</em><em> </em><em>F</em><em>/</em><em>m</em>

<em>a</em><em> </em><em>=</em><em> </em><em>1</em><em>2</em><em>N</em><em>/</em><em>5</em><em>k</em><em>g</em>

<em>a</em><em> </em><em>=</em><em> </em><em>2</em><em>.</em><em>4</em><em> </em><em>m</em><em>/</em><em>s</em><em>^</em><em>2</em>

<em>T</em><em>h</em><em>e</em><em>r</em><em>e</em><em>f</em><em>o</em><em>r</em><em>e</em><em>,</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>a</em><em>c</em><em>c</em><em>e</em><em>l</em><em>a</em><em>r</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>o</em><em>f</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>o</em><em>b</em><em>j</em><em>e</em><em>c</em><em>t</em><em> </em><em>i</em><em>s</em><em> </em><em>2</em><em>.</em><em>4</em><em> </em><em>m</em><em>/</em><em>s</em><em>^</em><em>2</em>

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A closed system’s internal energy changes by 178 J as a result of being heated with 658 J of energy. The energy used to do work
nika2105 [10]

Answer:

480J

Explanation:

Using the formula:

Delta U = Q - W

Q:Heat (J)

Delta U: Changes in internal Energy (J)

W:Work (J)

We can plug in the give numbers, Q and W.

Delta U = 658J - 178J = 480J

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Explanation:

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PilotLPTM [1.2K]

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present

Explanation:

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3 years ago
An astronaut who is repairing the outside of her spaceship accidentally pushes away a 92.9 cm long steel rod, which flies off at
DiKsa [7]

Answer:

V = 0.0723 volts = 72.3 milivolts

Explanation:

The emf induced in the rod is the motional emf due to the magnetic field. This motional emf can be calculated by the following formula:

EMF = V = vBl Sin\theta

where,

V = Motional EMF = ?

v = speed of rod = 12.5 m/s

B = Magnetic Field = 6.23 mT = 0.00623 T

l = Length of rod = 92.9 cm = 0.929 m

θ = angle between v and B = 90°

Therefore,

V = (12.5\ m/s)(0.00623\ T)(0.929\ m)Sin\ 90^o\\

<u>V = 0.0723 volts = 72.3 milivolts</u>

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