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MatroZZZ [7]
3 years ago
11

State the Newton's first law of motion in words and in mathematical form.

Physics
1 answer:
Effectus [21]3 years ago
5 0

<em>Newton's First Law</em>

<em>*</em><em> </em><em>Newton's First Law of Motion states that a body will remain at rest or will continue to move at a constant velocity, unless an external force is applied.</em>

<em>*</em><em> </em><em>This means that in order for the acceleration of a body to change, there must be a net force applied to the body. Put another way, if the forces on an object balance, there will be no acceleration (the object will continue at the same speed).So, if we are told that a body is not accelerating (i.e. if it is moving at a constant velocity), we know that the resultant (overall) force in any one direction will be zero.</em>

<em>*</em><em> </em><em> </em><em>I</em><em>t</em><em>s</em><em> </em><em>a</em><em>n</em><em> </em><em>u</em><em>n</em><em>b</em><em>a</em><em>l</em><em>a</em><em>n</em><em>c</em><em>e</em><em>d</em><em> </em><em>f</em><em>o</em><em>r</em><em>c</em><em>e</em><em>,</em>

<em> </em><em>8</em><em>N</em><em> </em><em>a</em><em>c</em><em>t</em><em>i</em><em>n</em><em>g</em><em> </em><em>t</em><em>o</em><em>w</em><em>a</em><em>r</em><em>d</em><em>s</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>l</em><em>e</em><em>f</em><em>t</em><em>,</em><em> </em><em>a</em><em>n</em><em>d</em><em> </em><em>2</em><em>0</em><em>N</em><em> </em><em>a</em><em>c</em><em>t</em><em>i</em><em>n</em><em>g</em><em> </em><em>t</em><em>o</em><em>w</em><em>a</em><em>r</em><em>d</em><em>s</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>r</em><em>i</em><em>g</em><em>h</em><em>t</em><em>.</em>

<em>F</em><em> </em><em>=</em><em> </em><em>F</em><em>2</em><em> </em><em>-</em><em> </em><em>F</em><em>1</em>

<em>=</em><em> </em><em>2</em><em>0</em><em>N</em><em> </em><em>-</em><em> </em><em>8</em><em>N</em>

<em>=</em><em> </em><em>1</em><em>2</em><em>N</em>

<em>F</em><em> </em><em>=</em><em> </em><em>m</em><em>a</em>

<em>a</em><em> </em><em>=</em><em> </em><em>F</em><em>/</em><em>m</em>

<em>a</em><em> </em><em>=</em><em> </em><em>1</em><em>2</em><em>N</em><em>/</em><em>5</em><em>k</em><em>g</em>

<em>a</em><em> </em><em>=</em><em> </em><em>2</em><em>.</em><em>4</em><em> </em><em>m</em><em>/</em><em>s</em><em>^</em><em>2</em>

<em>T</em><em>h</em><em>e</em><em>r</em><em>e</em><em>f</em><em>o</em><em>r</em><em>e</em><em>,</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>a</em><em>c</em><em>c</em><em>e</em><em>l</em><em>a</em><em>r</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>o</em><em>f</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>o</em><em>b</em><em>j</em><em>e</em><em>c</em><em>t</em><em> </em><em>i</em><em>s</em><em> </em><em>2</em><em>.</em><em>4</em><em> </em><em>m</em><em>/</em><em>s</em><em>^</em><em>2</em>

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Answer:

U2 = 47.38m/s = initial velocity of B before impact

Explanation:

An example of the diagram is shown in the attached file because of missing angle of direction in the question

Mass A, B are mass of cars

A = 1965

B =1245

U1 = initial velocity of A = 52km/hr

U2 = initial velocity of B

V = common final velocity of two cars

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25 POINTS FOR CORRECT ANSWER
castortr0y [4]
No.  I do not agree with Stefan.  Quite the contrary.  I disagree
with his description of "<span>angle of incidence" as the angle between
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Thus, the true angle of incidence is the complement of the angle that
Stefan calculates or measures.</span>
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