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MatroZZZ [7]
3 years ago
11

State the Newton's first law of motion in words and in mathematical form.

Physics
1 answer:
Effectus [21]3 years ago
5 0

<em>Newton's First Law</em>

<em>*</em><em> </em><em>Newton's First Law of Motion states that a body will remain at rest or will continue to move at a constant velocity, unless an external force is applied.</em>

<em>*</em><em> </em><em>This means that in order for the acceleration of a body to change, there must be a net force applied to the body. Put another way, if the forces on an object balance, there will be no acceleration (the object will continue at the same speed).So, if we are told that a body is not accelerating (i.e. if it is moving at a constant velocity), we know that the resultant (overall) force in any one direction will be zero.</em>

<em>*</em><em> </em><em> </em><em>I</em><em>t</em><em>s</em><em> </em><em>a</em><em>n</em><em> </em><em>u</em><em>n</em><em>b</em><em>a</em><em>l</em><em>a</em><em>n</em><em>c</em><em>e</em><em>d</em><em> </em><em>f</em><em>o</em><em>r</em><em>c</em><em>e</em><em>,</em>

<em> </em><em>8</em><em>N</em><em> </em><em>a</em><em>c</em><em>t</em><em>i</em><em>n</em><em>g</em><em> </em><em>t</em><em>o</em><em>w</em><em>a</em><em>r</em><em>d</em><em>s</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>l</em><em>e</em><em>f</em><em>t</em><em>,</em><em> </em><em>a</em><em>n</em><em>d</em><em> </em><em>2</em><em>0</em><em>N</em><em> </em><em>a</em><em>c</em><em>t</em><em>i</em><em>n</em><em>g</em><em> </em><em>t</em><em>o</em><em>w</em><em>a</em><em>r</em><em>d</em><em>s</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>r</em><em>i</em><em>g</em><em>h</em><em>t</em><em>.</em>

<em>F</em><em> </em><em>=</em><em> </em><em>F</em><em>2</em><em> </em><em>-</em><em> </em><em>F</em><em>1</em>

<em>=</em><em> </em><em>2</em><em>0</em><em>N</em><em> </em><em>-</em><em> </em><em>8</em><em>N</em>

<em>=</em><em> </em><em>1</em><em>2</em><em>N</em>

<em>F</em><em> </em><em>=</em><em> </em><em>m</em><em>a</em>

<em>a</em><em> </em><em>=</em><em> </em><em>F</em><em>/</em><em>m</em>

<em>a</em><em> </em><em>=</em><em> </em><em>1</em><em>2</em><em>N</em><em>/</em><em>5</em><em>k</em><em>g</em>

<em>a</em><em> </em><em>=</em><em> </em><em>2</em><em>.</em><em>4</em><em> </em><em>m</em><em>/</em><em>s</em><em>^</em><em>2</em>

<em>T</em><em>h</em><em>e</em><em>r</em><em>e</em><em>f</em><em>o</em><em>r</em><em>e</em><em>,</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>a</em><em>c</em><em>c</em><em>e</em><em>l</em><em>a</em><em>r</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>o</em><em>f</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>o</em><em>b</em><em>j</em><em>e</em><em>c</em><em>t</em><em> </em><em>i</em><em>s</em><em> </em><em>2</em><em>.</em><em>4</em><em> </em><em>m</em><em>/</em><em>s</em><em>^</em><em>2</em>

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Three importance of SI system​
diamong [38]

Answer:

Firstly they are, by design, easy to use in most scientific and engineering calculations; you only ever have to consider multiples of 10. If I’m given a measurement of 3.4 kilometres, I can instantly see that it’s 3′400 metres, or 0.0034 Megametres, or 3′400′000 millimetres. It’s not even necessary to use arithmetic, I just have to remember the definitions of the prefixes (“kilo” is a thousand, “megametre” is a million, “milli” is a thousandth) and shift the decimal point across to the left or the right. This is especially useful when we’re considering areas, speeds, energies, or other things that have multiple units; for instance,

1 metre^2 = (1000millimetre)^2 = 1000000 mm^2.

If we were to do an equivalent conversion in Imperial, we would have

1 mile^2 = (1760 yards)^2

and we immediately have to figure out what the square of 1760 is! However, the fact that SI is based on multiples of 10 has the downside that we can’t consider division by 3, 4, 8, or 12 very easily.

Secondly they are (mostly) defined in terms of things that are (or, that we believe to be) fundamental constants. The second is defined by a certain kind of radiation that comes from a caesium atom. The metre is defined in terms of the second and the speed of light. The kelvin is defined in terms of the triple point of water. The mole is the number of atoms in 12 grams of carbon-12. The candela is defined in terms of the light intensity you get from a very specific light source. The ampere is defined using the Lorentz force between two wires. The only exception is the kilogram, which is still defined by the mass of a very specific lump of metal in a vault in France (we’re still working on a good definition for that one).

Thirdly, most of the Imperial and US customary units are defined in terms of SI. Even if you’re not personally using SI, you are probably using equipment that was designed using SI.

8 0
3 years ago
The potential energy of a particle as a function of position will be given as U(x) = A x2 + B x + C, where U will be in joules w
satela [25.4K]

Answer:

F = - 2 A x - B

Explanation:

The force and potential energy are related by the expression

      F = - dU / dx i ^ -dU / dy j ^ - dU / dz k ^

Where i ^, j ^, k ^ are the unit vectors on the x and z axis

The potential they give us is

     U (x) = A x² + B x + C

Let's calculate the derivatives

    dU / dx = A 2x + B + 0

The other derivatives are zero because the potential does not depend on these variables.

Let's calculate the strength

      F = - 2 A x - B

3 0
3 years ago
Striking a match stick on the matchbox involves the reaction of potassium chlorate and red phosphorus with the following equatio
yarga [219]

Answer:

m(P4) =  46.175 (grams)

m (KClO3) = 149 (grams)


Explanation:

1) n(P4) = n(P4O10);

m(P4)/M(P4) = m(P4O10)/M(P4O10);

m(P4) = M(P4)*m(P4O10)/M(P4O10)
          = 123.90*105.8/283.89
          = 46.175 (grams)

2) Analogously, 10n(P4O10) = 3n(KClO3)

m (KClO3) = 10M(KClO3)*m(P4O10)/3M(P4O10)
                = 10*122.55*105.8/283.89/3
                = 149 (grams).

6 0
2 years ago
Explain why the duster accelerates different rates when different surfaces are in contact with the track
vichka [17]

Answer:

Because on different surfaces there's more/less friction. Smooth surfaces will allow the duster to accelerate while rough surfaces will decrease the acceleration.

8 0
3 years ago
Read 2 more answers
A women who normally weighs 400 N stands on top of a ladder so high she is one full additional earth radius above the surface of
AveGali [126]

The woman weighs 100N now.

Explanation:

Given:

F is given as 400N

one full additional earth radius formed

To Find:

Weight of the woman=?

Solution:

We know that gravitational force is inversely proportional to the square of radius.

f_g=\frac{1}{r^2}

where

f_g is the gravitational force

r^2 is the radius square

So when radius is doubled, the force becomes one fourth of the original.

Therefore \frac{1}{4} \times400 = 100N

3 0
3 years ago
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