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MatroZZZ [7]
3 years ago
11

State the Newton's first law of motion in words and in mathematical form.

Physics
1 answer:
Effectus [21]3 years ago
5 0

<em>Newton's First Law</em>

<em>*</em><em> </em><em>Newton's First Law of Motion states that a body will remain at rest or will continue to move at a constant velocity, unless an external force is applied.</em>

<em>*</em><em> </em><em>This means that in order for the acceleration of a body to change, there must be a net force applied to the body. Put another way, if the forces on an object balance, there will be no acceleration (the object will continue at the same speed).So, if we are told that a body is not accelerating (i.e. if it is moving at a constant velocity), we know that the resultant (overall) force in any one direction will be zero.</em>

<em>*</em><em> </em><em> </em><em>I</em><em>t</em><em>s</em><em> </em><em>a</em><em>n</em><em> </em><em>u</em><em>n</em><em>b</em><em>a</em><em>l</em><em>a</em><em>n</em><em>c</em><em>e</em><em>d</em><em> </em><em>f</em><em>o</em><em>r</em><em>c</em><em>e</em><em>,</em>

<em> </em><em>8</em><em>N</em><em> </em><em>a</em><em>c</em><em>t</em><em>i</em><em>n</em><em>g</em><em> </em><em>t</em><em>o</em><em>w</em><em>a</em><em>r</em><em>d</em><em>s</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>l</em><em>e</em><em>f</em><em>t</em><em>,</em><em> </em><em>a</em><em>n</em><em>d</em><em> </em><em>2</em><em>0</em><em>N</em><em> </em><em>a</em><em>c</em><em>t</em><em>i</em><em>n</em><em>g</em><em> </em><em>t</em><em>o</em><em>w</em><em>a</em><em>r</em><em>d</em><em>s</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>r</em><em>i</em><em>g</em><em>h</em><em>t</em><em>.</em>

<em>F</em><em> </em><em>=</em><em> </em><em>F</em><em>2</em><em> </em><em>-</em><em> </em><em>F</em><em>1</em>

<em>=</em><em> </em><em>2</em><em>0</em><em>N</em><em> </em><em>-</em><em> </em><em>8</em><em>N</em>

<em>=</em><em> </em><em>1</em><em>2</em><em>N</em>

<em>F</em><em> </em><em>=</em><em> </em><em>m</em><em>a</em>

<em>a</em><em> </em><em>=</em><em> </em><em>F</em><em>/</em><em>m</em>

<em>a</em><em> </em><em>=</em><em> </em><em>1</em><em>2</em><em>N</em><em>/</em><em>5</em><em>k</em><em>g</em>

<em>a</em><em> </em><em>=</em><em> </em><em>2</em><em>.</em><em>4</em><em> </em><em>m</em><em>/</em><em>s</em><em>^</em><em>2</em>

<em>T</em><em>h</em><em>e</em><em>r</em><em>e</em><em>f</em><em>o</em><em>r</em><em>e</em><em>,</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>a</em><em>c</em><em>c</em><em>e</em><em>l</em><em>a</em><em>r</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>o</em><em>f</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>o</em><em>b</em><em>j</em><em>e</em><em>c</em><em>t</em><em> </em><em>i</em><em>s</em><em> </em><em>2</em><em>.</em><em>4</em><em> </em><em>m</em><em>/</em><em>s</em><em>^</em><em>2</em>

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You connect a 100-resistor, a 800-mH inductor, and a 10.0-uF capacitor in series across a 60.0-Hz, 120-V (peak) source. The impe
steposvetlana [31]

Answer:

Impedance, Z = 107 ohms

Explanation:

It is given that,

Resistance, R = 100 ohms

Inductance, L=800\ mH=800\times 10^{-3}\ H=0.8\ H

Capacitance, C=10\ \mu F=10\times 10^{-6}\ F=10^{-5}\ F

Frequency, f = 60 Hz

Voltage, V = 120 V

The impedance of the circuit is given by :

Z=\sqrt{R^2+(X_C-X_L)^2}...........(1)

Where

X_C is the capacitive reactance, X_C=\dfrac{1}{2\pi fC}

X_C=\dfrac{1}{2\pi \times 60\times 10^{-5}}=265.65\ \Omega

X_L is the inductive reactance, X_L={2\pi fL}

X_L={2\pi \times 60\times 0.8}=301.59\ \Omega

So, equation (1) becomes :

Z=\sqrt{(100)^2+(265.65-301.59)^2}

Z = 106.26 ohms

or

Z = 107 ohms

So, the impedance of the circuit is 107 ohms. Hence, this is the required solution.

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Select the correct answer.
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Two identical masses are connected to two different flywheels that are initially stationary. Flywheel A is larger and has more m
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Answer:

a) True. There is dependence on the radius and moment of inertia, no data is given to calculate the moment of inertia

c) True. Information is missing to perform the calculation

Explanation:

Let's consider solving this exercise before seeing the final statements.

We use Newton's second law Rotational

      τ = I α

     T r = I α

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Now let's use Newton's second law in the mass that descends

     W- T = m a

     a = (m g -T) / m

The two accelerations need related

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    a = (m g - α I / R) / m

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    α = g / R (1 + I / mR²)

We can see that the angular acceleration depends on the radius and the moments of inertia of the steering wheels, the mass is constant

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a) True. There is dependence on the radius and moment of inertia, no data is given to calculate the moment of inertia

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Explanation:

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