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Pie
3 years ago
11

A local car dealership sells Buicks and Hondas. The following data shows the number of buyers this month according to the brand

of car they purchased as well as their age group.Age Buick HondaUnder 40 years old 6 17 40 years or older 19 8 What is the percentage of buyers 40 years or older and purchased a​Honda?
Mathematics
1 answer:
Lina20 [59]3 years ago
8 0

Answer:

16%

Step-by-step explanation:

The data provided on brand purchased by age group is.

\begin{array}{ccc}Age&Buick&Honda\\Under\ 40&6&17\\40\ or\ older&19&8\end{array}

A total of 50 cars were sold this month.

Since the number of buyers 40 years or older that purchased a ​Honda is 8, the percentage is:

P=\frac{8}{50}=0.16=16\%

16% of buyers were 40 years or older and purchased a​ Honda.

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3 years ago
35 rounded to the nearest hundred
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Answer and Explanation: 35 rounded to the nearest 100 is 0. To round to the nearest hundred, you need to first identify the hundreds that are closest to the number you are rounding. For 35, the closest hundred that is lower than 35 is 0, and the closest 100 that is higher than 35 is 100.

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Which equation has no solution?
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What is 4n-32? Factor your expression using the greatest common factor.
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Answer:

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Step-by-step explanation:

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2 years ago
Solve the given system of equations using either Gaussian or Gauss-Jordan elimination. (If there is no solution, enter NO SOLUTI
cricket20 [7]

Answer:

The system has infinitely many solutions

\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}

Step-by-step explanation:

Gauss–Jordan elimination is a method of solving a linear system of equations. This is done by transforming the system's augmented matrix into reduced row-echelon form by means of row operations.

An Augmented matrix, each row represents one equation in the system and each column represents a variable or the constant terms.

There are three elementary matrix row operations:

  1. Switch any two rows
  2. Multiply a row by a nonzero constant
  3. Add one row to another

To solve the following system

\begin{array}{ccccc}x_1&-3x_2&-2x_3&=&0\\-x_1&2x_2&x_3&=&0\\2x_1&+3x_2&+5x_3&=&0\end{array}

Step 1: Transform the augmented matrix to the reduced row echelon form

\left[ \begin{array}{cccc} 1 & -3 & -2 & 0 \\\\ -1 & 2 & 1 & 0 \\\\ 2 & 3 & 5 & 0 \end{array} \right]

This matrix can be transformed by a sequence of elementary row operations

Row Operation 1: add 1 times the 1st row to the 2nd row

Row Operation 2: add -2 times the 1st row to the 3rd row

Row Operation 3: multiply the 2nd row by -1

Row Operation 4: add -9 times the 2nd row to the 3rd row

Row Operation 5: add 3 times the 2nd row to the 1st row

to the matrix

\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

The reduced row echelon form of the augmented matrix is

\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

which corresponds to the system

\begin{array}{ccccc}x_1&&-x_3&=&0\\&x_2&+x_3&=&0\\&&0&=&0\end{array}

The system has infinitely many solutions.

\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}

7 0
3 years ago
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