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3 years ago

Find the values of x and y : EK= 7x+5, KG= 3x+17, HK= 3y-11, KF= y+5NEED ANSWER ASAP

Mathematics

1 answer:

Mice21 [21]3 years ago

3 0

Answer:

Step-by-step explanation:

We know:

The diagonals of the parallelogram are divided in half.

Therefore

EK ≅ KG and HK ≅ KF.

We have

EK = 7x + 5, KG = 3x + 17, HK = 3y - 11 and KF = y + 5

Equations:

(1) 7x + 5 = 3x + 17

(2) 3y - 11 = y + 5

Solutions:

(1)

7x + 5 = 3x + 17 subtract 5 from both sides

7x + 5 - 5 = 3x + 17 - 5

7x = 3x + 12 subtract 3x from both sides

7x - 3x = 3x - 3x + 12

4x = 12 divide both sides by 4

4x/4 = 12/4

x = 3

------------------------------

(2)

3y - 11 = y + 5 add 11 to both sides

3y - 11 + 11 = y + 5 + 11

3y = y + 16 subtract y from both sides

3y - y = y - y + 16

2y = 16 divide both sides by 2

2y/2 = 16/2

y = 8

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3 years ago

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