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Pani-rosa [81]
3 years ago
5

4 7,304 x 66 = (2 Points) Enter your answer

Mathematics
1 answer:
guapka [62]3 years ago
3 0

i think the answer is 482,064?

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60 cars to 24 cars what is the percent of change can you tell me answer and explain thanks
ankoles [38]
Assuming you meant there were 60 cars and then 36 went off somewhere and you are left with 24 cars, the percent of change is 250% because 60/24=2.5, multiply that by 100 (to get percent) will get you 250%.
3 0
3 years ago
Add 11/6x and 2/13x<br><br> Add 11/6x and 2/13x
Natalija [7]

Answer:

Hii the correct answeeer is B.

8 0
3 years ago
Anna wants to factor the polynomial p(x)=5x^4+40x. She knows that the sum of cubes formula is a^3+b^3=(a+b)(a^2−ab+b^2).
Artemon [7]

Answer:

Part A:  Option 2, A: Anna’s answer is incorrect. She correctly factored out 5x, but incorrectly identified a and b, so her answer cannot be correct.

Part B:  Option 3, B: 5x(x+2)(x^2−2x+4)

Step-by-step explanation:

p(x) = 5x^4 + 40x

p(x) = 5x(x^3 + 8)

p(x) = 5x(x + 2)(x^2 - 2x + 4)

Part A:  Option 2, A: Anna’s answer is incorrect. She correctly factored out 5x, but incorrectly identified a and b, so her answer cannot be correct.

Part B:  Option 3, B: 5x(x+2)(x^2−2x+4)

7 0
3 years ago
Write 800 as the product of its prime factors.
Alex_Xolod [135]
800|2
800|2
400|2
200|2
100|2
50|2
25|5
5|5
1

800=2^5\cdot5^2


8 0
4 years ago
The owner of a cattle ranch would like to fence in a rectangular area of 3000000 m^2 and then divide it in half with a fence dow
Reika [66]
If you notice the picture below, the amount of fencing, or perimeter, that will be used will be 3w + 2l

now    \bf \begin{cases}&#10;A=l\cdot w\\\\\&#10;A=3000000\\&#10;----------\\&#10;3000000=l\cdot w\\\\&#10;\frac{3000000}{w}=l&#10;\end{cases}\qquad thus&#10;\\\\\\&#10;P=3w+2l\implies P=3w+2\left( \cfrac{3000000}{w} \right)\implies P=3w+\cfrac{6000000}{w}&#10;\\\\\\&#10;P=3w+6000000w^{-1}\\\\&#10;-----------------------------\\\\&#10;now\qquad \cfrac{dP}{dw}=3-\cfrac{6000000}{w^2}\implies \cfrac{dP}{dw}=\cfrac{3w^2-6000000}{w^2}&#10;\\\\\\&#10;\textit{so the critical points are at }&#10;\begin{cases}&#10;0=w^2\\\\&#10;0=\frac{3w^2-6000000}{w^2}&#10;\end{cases}

solve for "w", to see what critical points you get, and then run a first-derivative test on them, for the minimum

notice the 0=w^2\implies 0=w   so.  you can pretty much skip that one, though is a valid critical point, the width can't clearly be 0

so.. check the critical points on the other

8 0
3 years ago
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