The grams  of FeO  that would  be needed to make 234.2 grams  of Fe  is
1204.42 grams
<u><em> calculation</em></u>
4 FeO → Fe₃O₄ +Fe
Step 1: find the  moles  of  fe
moles  =  mass /molar mass
from periodic table the  molar mass of Fe  = 56 g/mol
 moles = 234.2 g/56 g/mol = 4.182  moles
Step 2: use  the mole ratio to determine the moles of  FeO
FeO: Fe  is 4:1 therefore the  moles of FeO  =4.182 moles  x4 =16.728  moles
Step 3:   find  the mass of FeO
 mass = moles  x molar  mass
 The molar mass of FeO = 56 +16 = 72 g /mol
mass  = 16.728 moles  x 72 g/mol= 1204.42 grams