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Kitty [74]
3 years ago
7

If the air temperature is the same as the temperature of your skin (about 30◦C), your body cannot get rid of heat by transferrin

g it to the air. In that case, it gets rid of the heat by evaporating water (sweat). During bicycling, a typical 60-kg person’s body produces energy at a rate of about 500 W due to metabolism, 80% of which is converted to heat. (a) How many kilograms of water must the person’s body evaporate in an hour to get rid of this heat? The heat of vaporization of water at body temperature is 2.42 × 106 J/kg. (b) The evaporated water must, of course, be replenished, or the person will dehydrate. How many 750-mL bottles of water must the bicyclist drink per hour to replenish the lost water? (Recall that the mass of a liter of water is 1.0 kg.)
Chemistry
1 answer:
Elenna [48]3 years ago
8 0

Answer:

Explanation:

a )

energy produced per second = 500 J

Heat produced = 500 x .8 = 400 J per second.

If m be the mass of water evaporated per unit hour

m x latent heat = 400 x 60 x 60

= m x 2.42 x 10⁶ = 1.44 x 10⁶

m = .595 kg per hour

b )

volume of water = 595 mL

bottles = 595 / 750

.8 or 4/5 of bottle. per hour.

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2) Show the calculation of Kc for the following reaction if an initial reaction mixture of 0.800 mole of CO and 2.40 mole of H2
nadezda [96]

Answer:

Kc = 3.90

Explanation:

CO reacts with H_2 to form CH_4 and H_2O. balanced reaction is:

CO(g) + 3H_2 (g) \leftrightharpoons CH_4(g)  +  H_2O(g)

No. of moles of CO = 0.800 mol

No. of moles of H_2 = 2.40 mol

Volume = 8.00 L

Concentration = \frac{Moles}{Volume\ in\ L}

Concentration of CO = \frac{0.800}{8.00} = 0.100\ mol/L

Concentration of H_2 = \frac{2.40}{8.00} = 0.300\ mol/L

                 CO(g) + 3H_2 (g) \leftrightharpoons CH_4(g)  +  H_2O(g)

Initial            0.100      0.300             0   0

equi.            0.100 -x    0.300 - 3x     x    x

It is given that,

at equilibrium H_2O (x) = 0.309/8.00 = 0.0386 M

So, at equilibrium CO = 0.100 - 0.0386 = 0.0614 M

At equilibrium H_2 = 0.300 - 0.0386 × 3 = 0.184 M

At equilibrium CH_4 = 0.0386 M

Kc=\frac{[H_2O][CH_4]}{[CO][H_2]^3}

Kc=\frac{0.0386 \times 0.0386}{(0.184)^3 \times 0.0614} =3.90

8 0
4 years ago
How many molecules of lactate can one molecule of lactate dehydrogenase act on in 21 minutes?
USPshnik [31]
The turnover number (number of molecules the enzyme can act on per second) for lactase dehydrogenase is 1,000 lactate molecules per second.
In one minute, this becomes:

(1,000 molecules / second) * (60 seconds / minute)
= 60,000 molecules / minute

In 21 minutes, this will be:

60,000 * 21

= 1.26 x 10⁶ molecules of lactate
6 0
4 years ago
प्रश्न 01. बेकिंग सोडा बनाने के लिए आवश्यक सामग्री निर्माण की विधि एंव रासायनिक<br>समीकरण लिखिए।​
salantis [7]

Answer:

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6 0
3 years ago
What is the wavelength of the line corresponding to n=4 in the balmer series? express your answer in nanometers to three signifi
liq [111]
Expression for the Balmer series to find the wavelength of the spectral line is as follows:
1 / λ = R (\frac{1}{2^{2} } -  \frac{1}{ n^{2}} )
Where, λ is wavelength, R is Rydberg constant, and n is integral value (4 here →  Fourth level) 
Substitute 1.097 x 10⁷ m⁻¹ for R and 4 for n in the above equation 
1 / λ = (1.097 x 10⁷ m⁻¹) (\frac{1}{2^{2} } -  \frac{1}{4^{2} }  ) 
   = 0.20568 x 10⁷ m⁻¹
λ = 4.86 x 10⁻⁷ m 
since 1 m = 10⁹ nm
λ = 486 nm 
8 0
3 years ago
The graph below shows how the temperature and volume of a gas vary when
Sever21 [200]

Answer:

C

Explanation:

because it remains the same

3 0
3 years ago
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