Question

If the air temperature is the same as the temperature of your skin (about 30◦C), your body cannot get rid of heat by transferring it to the air. In that case, it gets rid of the heat by evaporating water (sweat). During bicycling, a typical 60-kg person’s body produces energy at a rate of about 500 W due to metabolism, 80% of which is converted to heat. (a) How many kilograms of water must the person’s body evaporate in an hour to get rid of this heat? The heat of vaporization of water at body temperature is 2.42 × 106 J/kg. (b) The evaporated water must, of course, be replenished, or the person will dehydrate. How many 750-mL bottles of water must the bicyclist drink per hour to replenish the lost water? (Recall that the mass of a liter of water is 1.0 kg.)

Answer 1

Answer:

Explanation:

a )

energy produced per second = 500 J

Heat produced = 500 x .8 = 400 J per second.

If m be the mass of water evaporated per unit hour

m x latent heat = 400 x 60 x 60

= m x 2.42 x 10⁶ = 1.44 x 10⁶

m = .595 kg per hour

b )

volume of water = 595 mL

bottles = 595 / 750

.8 or 4/5 of bottle. per hour.