Two systems of equations are shown below:. System A. 3x + 2y = 3. –2x - 8y = –1. System B. –x - 14y = 1. –2x – 8y = –1. Which of
the following statements is correct about the two systems of equations?. The value of x for System B will be one–third of the value of x for System A because the coefficient of x in the first equation of System B is one third times the coefficient of x in the first equation of System A.
We can solve for both x and y of System A and B to compare the values of x.
System A. Multiply by 4 the first equation and add both equations, 12x + 8y = 12 + -2x - 8y = -1 We will be left with equation, 10x = 11 The value of x is 11/10
System B. Multiply the first equation by -2 and add the equations, 2x + 28y = -2 + -2x - 8y = -1 We will be left with 20y = -3. Substitute the value of y to any of the equations. This gives a value of x equal to 11/10.
The answer therefore is that both systems will have the same value of x's.
To compare the values of x, we need to obtain the values of x for both systems.
For system A. Multiply the first equation by 4 and add the equations, 12x + 8y = 12 + -2x - 8y = -1 It will yield, 10x = 11 Then, the value of x is 11/10.
For system B. Multiply the first equation by -2 and add the equations given, 2x + 28y = -2 + -2x - 8y = -1 It will yield, 20y = -3
We substitute the value of y to any of the equations in system B. This gives a value of x which is equal to 11/10.
<span>Therefore, both systems will have the same value of x.</span>
I'm not exactly sure but I think it might be but if you were to do 4(x-7) that would be 15 because fifteen minutes seven equals eight and eight time four is thirty two Hope this helps!
