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lisov135 [29]
3 years ago
10

Blaine exchanges $100 for yen before going to Japan. If each U.S. dollar is worth 88.353 yen,how many yen should Blaine receive?

Mathematics
1 answer:
Vaselesa [24]3 years ago
3 0
<span>To figure out how many yen all ya have to do is multiply 88.353 by 100 to get the answer 8835.3 yen</span>
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Boston, Massachusetts had a population of 617,594 people during January 1 2010, and 675,647 people on January 1 2020.
tigry1 [53]

Answer:

  • See below

Step-by-step explanation:

<u>Exponential function is:</u>

  • y = abˣ

<u>If we consider the time difference in years as x and the initial population as a, then we get:</u>

  • 675647 = 617594*b¹⁰

<u>Find the value of b:</u>

  • b¹⁰ = 675647/617594
  • b¹⁰ = 1.09399864636
  • b = 1.09399864636^(1/10)
  • b = 1.009 (rounded)

<u>The equation we got is:</u>

  • y = 617594*1.009ˣ

Here we have y- population after x years since 2010, x - the number of years since 2010 and 1.009 is the population growth rate.

5 0
2 years ago
A movie theater has a seating capacity of 387. The theater charges $5.00 for children, $7.00 for students, and $12.00 of
Rainbow [258]

Answer:

The attendance was 198 children, 90 students and 99 adults.

Step-by-step explanation:

We define:

c: children attendance

s: students attendance

a: adult attendance

The equation that describes the total ticket sales is:

5c+7s+12a=2808

We also know that the children attendance doubles the adult attendance:

c=2a

The third equation is the seating capacity, which we assume is full:

c+s+a=387

We start by replacing variables in two of the equations:

c=2a\\\\s=387-c-a=387-2a-a=387-3a

Then, we solve the remaining equation for a:

5c+7s+12a=2808\\\\5(2a)+7(387-3a)+12a=2808\\\\10a+(2709-21a)+12a=2808\\\\10a+12a-21a=2808-2709\\\\a=99

Then, we solve for the other two equations:

c=2a=2*99=198\\\\s=387-3a=387-3*99=387-297=90

The attendance was 198 children, 90 students and 99 adults.

8 0
4 years ago
Julie gives 7 pieces of candy to each of her friends. If Julie gives all of her candy away, which amount of candy could have bee
True [87]
To find the answer to this problem, you just need to figure out which total amount of candy is divisible by 7.

161/7=23
<span>162/7=23.1428571429
</span>145/7=<span>20.7142857143
128/7=</span><span>18.2857142857

Obviously, Julie cannot give a fraction of an amount of candy to someone.  So that rules out that she had 162, 145, or 128 pieces of candy.  

The only amount of candies that Julie could have that is divisible by 7 is 161 candies, which means that 161 is your answer.</span>
5 0
3 years ago
Read 2 more answers
An 'A' is considered 4.0, a 'B' is 3.0, a 'C' is 2.0, a 'D' is 1.0, and an 'F' is 0. If you received the following grades in you
Goryan [66]

Answer:

2.2gpa

Step-by-step explanation:

you add the value if the letter grades up and divide by how many classes you have. for this case you have 5 and you would add 4+3+2+1+0=10/5=2.2

7 0
4 years ago
8640 divided by40 long division
Tju [1.3M]
The answer is 216.
https://photomath.net/s/YLLqQX
7 0
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