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3 years ago

5(9-X)≤ 4(X+18) blalalalala

Mathematics

2 answers:

finlep [7]3 years ago

7 0

Answer:

x ≥ -3

Step-by-step explanation:

5(9-x)≤4(x+18)

45-5x≤4x+72

subtract 4 from both sides

45-9x≤72

subtract 45 from both sides

-9x≤27

divide by -9, but when you divide by a negative in an inequality you have to flip the sign

x≥-3

Oksana_A [137]3 years ago

6 0

Answer:

-3 ≤ x

Step-by-step explanation:

5(9-X)≤ 4(X+18)

Distribute on both sides

45 -5x ≤ 4x + 72

Add 5x to each side

45 -5x+5x ≤ 4x+5x + 72

45 ≤ 9x + 72

Subtract 72 from each side

45-72 ≤ 9x + 72 -72

-27 ≤ 9x

Divide by 9

-27/9 ≤ 9x/9

-3 ≤ x

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The following table shows the estimated populations and annual growth rates for four countries in the year 2000. Find the expect

Liula [17]

Answer:

After 25 years the population will be:

Australia: 22271200
China: 1580220878
Mexico: 157380127
Zaire: 112794819

Step-by-step explanation:

Growth rate problem that has a growth rate proportional to the population size can be solved using the equation:

P(t) = P₀eʳᵗ

t is your unit of time. It could be days, or hours, or minutes. It changes depending on each problem. In this problem, t is measured in years because you're jumping from 2000 to 2025. Years just makes the most sense to measure that leap in time.

P(t) is the population at time t. An example in this problem could be P(20) would be the population 20 years after the initial count. or maybe P(12) would be the population 12 years after the initial count. or P(0) would be the initial count of the population.

P₀ is the initial population at P(0)
r is the growth rate. Don't forget to convert the percentage to its decimal form

Now that everything is set out, lets use the equation to solve for our answer.

P(t) = P₀eʳᵗ

Australia:

$P(t)=(19169000)e^{(0.006)t}$

after 25 years

$P(25)=(19169000)e^{(0.006)(25)}=22271200.6$

China:

$P(t) = (1261832000)e^{(.009)t}$

after 25 years:

$P(25)=(1261832000)e^{(.009)(25)}=1580220878$

Mexico:

$P(t) = (100350000)e^{(0.018)t}$

after 25 years:

$P(25)=(100350000)e^{(0.018)(25)}=157380127.8$

Zaire:

$P(t) = (51965000)e^{(0.031)t}$

after 25 years:

$P(25)=(51965000)e^{(0.031)(25)}=112794819.9$

6 0

4 years ago

The manufacturing of a ball bearing is normally distributed with a mean diameter of 22 millimeters and a standard deviation of .

Misha Larkins [42]

Answer:

0.1507 or 15.07%.

Step-by-step explanation:

We have been given that the manufacturing of a ball bearing is normally distributed with a mean diameter of 22 millimeters and a standard deviation of .016 millimeters. To be acceptable the diameter needs to be between 21.97 and 22.03 millimeters.

First of all, we will find z-scores for data points using z-score formula.

$z=\frac{x-\mu}{\sigma}$ , where,