Answer:
A homozygous recessive pea plant would have genotype rr and the heterozygous plant would have genotype Rr. So after the crossing between these two individuals occurs the two offspring produced would be heterozygous and the other two would be homozygous recessive.
R r
r Rr rr
r Rr rr
Therefore the genotype ratio would be 1:1 and the phenotypic ratio would also be 1:1 in the F1 generation because half would be round and half would be wrinkled.
Answer:
A gene is a small section of DNA on a chromosome that codes for a particular sequence of amino acids, to make a specific protein. It is the unit of heredity, and may be copied and passed on to the next generation.
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Answer:
Gene Flow
Explanation:
Gene flow is when genetic material gets transferred from one population to another.
The enzyme Taq polymerase is required in the PCR process because it is the main enzyme that synthesizes the new DNA strands complementary to the template strand and without the activity of this enzyme the PCR will be useless and it cannot make the copy of the given strand in any way. Thus, this enzyme is very much necessary for the efficient working of the PCR.
Polymerase Chain Reaction is a very efficient technique that can able to detect and copy even a small amount of DNA by performing a set of reactions at different temperatures.
The PCR process begins with the denaturing of the template strand at 95°C, followed by annealing in which the appropriate primers bind to the single strands of DNA at 50-56°C, followed by extension at 72°C in which the thermostable Taq polymerase synthesizes the strand complementary to the template DNA.
Learn more about PCR here
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