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Arisa [49]
3 years ago
5

Heat conduction is a function of material property, temperature difference and fluid the geometry of the object. a) True b) Fals

e
Engineering
1 answer:
Nuetrik [128]3 years ago
7 0

Answer:

a)True

Explanation:

According to Fourier's law,It states that Heat transfer is directly proportionate to the temperature gradient.For unidirectional conduction

    q''\alpha\dfrac{dT}{dx}

Where q'' is the heat flux.

When This directly proportionate is remove then one constant will on that place and that constant is called conductivity of material.

  q''=K\dfrac{dT}{dx}

So total heat transfer Q

      Q=KA\dfrac{dT}{dx}

When conductivity (K) of material is not constant

K=K_0(a+bT)  where a,b are constant.

So from the above expression we can say that heat transfer in material will depend on temperature difference,material property and on on geometry of object.

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(a) For BCC iron, calculate the diameter of the minimum space available in an octahedral site at the center of the (010) plane,
Romashka-Z-Leto [24]

Answer:

a) diameter available = 0.0384 nm

b)The space  is smaller than the carbon atom which has a  radius of  0.077 nm and this simply means that the carbon atom will not conquer these sites

Explanation:

For BCC iron

From Appendix B given,select the lattice parameter ( a ) as = 0.2866 nm

The BCC iron has 4 atomic radii and therefore the body diagonal length = a(3)^\frac{1}{2}

expressing the atomic radius of the BCC iron

4r = a(3)^\frac{1}{2}

insert the value of (a) from appendix B which is = 0.2866 nm

4r = 0.2866 nm (3)^\frac{1}{2}

therefore  r =  0.4964 nm / 4 = 0.1241 nm

Refer again to appendix C given select the atomic radius of the BCC iron as = 0.1241 nm   assuming the atomic radius of the iron are the same

then the radius ratio = 0.62

Refer to the Figure 3.2 given, the amount of space required for an interstitial at the BCC position is between the atoms at the FCC position and also in this space there are two atoms that are equal to a radius of 0.2482 nm

The diameter of the minimum space available

d_{a} = a - r_{a}

r_{a}  = atomic radii = 0.2482 nm

a = 0.2666 nm

therefore

d_{a} = 0.2866 nm - 0.2482 nm = 0.0384 nm

comparing this to the diameter of a carbon atom

The space  is smaller than the carbon atom which has a  radius of  0.077 nm and this simply means that the carbon atom will not conquer these sites

7 0
3 years ago
Info security:
il63 [147K]

Answer:

True

Explanation:

Dual home host - it is referred to as the firewall that is incorporated with two or more networks. out of these two networks, one is assigned to the internal network and the other is for the network. The main purpose of the dual-homed host is to ensure that no Internet protocol traffic is induced between both the network.

The most simple example of a dual-homed host is a computing motherboard that is provided with two network interfaces.

7 0
4 years ago
6.03 Discussion: Then & Now - Safety
34kurt

Answer:

Information technology is important in our lives because it helps to deal with every day's dynamic things. Technology offers various tools to boost development and to exchange information. Both these things are the objective of IT to make tasks easier and to solve many problems.

6 0
3 years ago
Look told you i made it a meme
MrRa [10]

Answer:

Dam they be thinking we racist

Explanation:

5 0
3 years ago
Read 2 more answers
A trapezoidal section has a 5.0-ft bed width, 2.5-ft depth, and 1:1 side slope. Evaluate its geometric elements (Area, water dep
aleksley [76]

Answer:

a) 18.75 ft^2

b) 2.5 ft

c) 12.07 ft

d) 10 ft

e) 1.553 ft

f) 1.875 ft

Explanation:

Given data :

5.0-ft bed width, ( b )

2.5-ft depth ( y )

1 : 1 side slope

Evaluate

a) Area of trapezoidal section

A = by + my^2

we assume m = 1

A = [5 + (1 * 2.5 ) ] *2.5

   = ( 7.5 ) 2.5  = 18.75 ft^2

b) Calculate water depth

water depth = 2.5 ft

c) Calculate wetted perimeter

P = b + 2y √ 1 + m^2

  = 5 + (2.5*2) √ 1 + 1 ^2  =   12.07 ft

d) calculate top width

    T = b + 2my

       = 5 + 2 ( 1 * 2.5 ) = 10 ft

e) calculate hydraulic radius

R = A / P = 18.75 / 12.07

               = 1.553 ft

f) calculate hydraulic depth

 D = A / T = 18.75 / 10 = 1.875 ft

4 0
3 years ago
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